5614 Posted January 26, 2005 Posted January 26, 2005 if you have an exothermic reaction then heat is given out. so temperature increases... temp change is a positive value yet delta(temperature) will give you a negative number because the change in temperature, final temp value is greater than the initial temp. value, so the temperature change = initial temp - final temp = negative number. so we have: positive change for temperature negative delta(temperature) why is the change in temperature (delta) is negative whilst there is a positive change?
swansont Posted January 26, 2005 Posted January 26, 2005 "Change in" is usually defined as "final - initial"
5614 Posted January 26, 2005 Author Posted January 26, 2005 oh no, i've answered my own question with a bit of help from someone else... basically in an exothermic reaction there's an increase of temperature externally... however ΔH or delta(temperature) will be a negative number because ΔH applies to the system... with in the system there is a temperature loss (the energy is transferred to the 'outside') so outside there's a temperature loss and within the system using ΔH we can see there's a heat energy loss.
Silencer Posted January 26, 2005 Posted January 26, 2005 H is enthalpy, not temperature. That's very important to know.
5614 Posted January 26, 2005 Author Posted January 26, 2005 oh yeah, sorry... h = u + pV where: u = internal energy p = pressure v = volume ΔH = energy used in bond breaking reactions - energy released in bond making products. oh one sec, now i am confused! this paragraph: "ΔH or delta(temperature) will be a negative number because ΔH applies to the system... with in the system there is a temperature loss (the energy is transferred to the 'outside') so outside there's a temperature loss and within the system using ΔH we can see there's a heat energy loss." does it apply for ΔH or Δtemperature? or both?
5614 Posted January 27, 2005 Author Posted January 27, 2005 so if a liquid starts at 10 degrees and ends up at 20 degrees is Δ(temperature) 10 degrees (from 20 - 10)... or... -10 degrees (from 10 - 20)? i know this is true: For an exothermic reaction, ΔH is negative... (from a trusted website) but is H temperature, enthalpy or possibly both?
ed84c Posted January 27, 2005 Posted January 27, 2005 why would H be temperature? enthalpy is energy required.
5614 Posted January 27, 2005 Author Posted January 27, 2005 entalpy is the sum of the internal energy plus the product of the pressure times the volume of the gas in a system energy required.... if you mean energy required for a reaction to occur that's activation energy.
ed84c Posted January 27, 2005 Posted January 27, 2005 i meant energy required for all bonds to break- enrgy made.
Silencer Posted January 27, 2005 Posted January 27, 2005 You always do (final - initial). So in your example, 20 - 10 = 10 C change. I'm lazy and don't know the latex and such that the forum uses, so you can deal with the un-pretty math.
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