Guest RyanL Posted January 27, 2005 Posted January 27, 2005 As a question last class our prof threw this one to us; Use the intermediated value theorem to show that there is some angle theta radians btw 0 and pi that sintheta=theta + 1 After looking at this however either I'm missing something really basic or this problem isn't right. No angle theta would fufill that equation because sin can only be 1, so theta would have to equal 0, and sin(0) isn't 1. Is there something I'm missing or did the prof mess up?
Dave Posted January 27, 2005 Posted January 27, 2005 I think you may be looking at it the wrong way Look at that equation for a minute. We can't use the IVT on an equation, so you need to define a function f(t) = sin(t) - t -1, and then because we're looking between 0 and pi, have f : [0,pi] -> R. f(0) = -1 and f(pi) = pi - 1. Moreover, f(pi) > f(0). So you should be able to apply the IVT from here.
bloodhound Posted January 27, 2005 Posted January 27, 2005 but , sinx = x + 1 doesnt have a positive real solution. that is obvious from drawing the two graphs.
Dave Posted January 27, 2005 Posted January 27, 2005 There is that. I swear I'm getting worse and worse at maths
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now