seppy93 Posted July 25, 2013 Posted July 25, 2013 10.00 mL aliquot of a triprotic acid is reacted with 27.42 mL 0.168M KOH solution. Determine the molar mass of the acid. I'm not sure how can I find the mass of the acid, because I don't see anything mass-related to the acid. And also, does the "aliquot" affect anything?
John Cuthber Posted July 25, 2013 Posted July 25, 2013 Well, you are right. There is not enough information to answer the question. Are you sure you have copied it correctly? If you have then someone else has made a mistake.
Function Posted September 8, 2013 Posted September 8, 2013 Small question in order to help you: what's the meaning of "0.168M"?
Function Posted October 15, 2013 Posted October 15, 2013 Given: Vacid = 0,01 L VKOH = 0,02742 L cKOH = 0,168 M = 0,168 moles/L Asked: Macid = [math]\frac{m_{acid}}{n_{acid}}[/math] Conclusion: too few information given
daniton Posted October 16, 2013 Posted October 16, 2013 I don't think there is no enough info. If the acid reacts with the base completely then there moles must be equal. Which is .068*27.42== the mole of the acid ,then you can proceed.
John Cuthber Posted October 16, 2013 Posted October 16, 2013 I don't think there is no enough info. If the acid reacts with the base completely then there moles must be equal. Which is .068*27.42== the mole of the acid ,then you can proceed. Why do you think there's enough information when three people have pointed out that there isn't? If you are sure there's enough information, why not just answer the question? That would prove the point.
daniton Posted October 19, 2013 Posted October 19, 2013 (edited) John Cuthber are you challenging me. I was only pointing out my idea. you could agree or disagree on the point. So, what do you think? Edited October 19, 2013 by daniton
John Cuthber Posted October 19, 2013 Posted October 19, 2013 There is not enough information to answer the question. Why do you think there is?
daniton Posted October 19, 2013 Posted October 19, 2013 (edited) Sorry my bad I was expecting the formula of the triprotic acid Edited October 19, 2013 by daniton
Wentworth Miller Posted October 21, 2013 Posted October 21, 2013 can anyone tell any information about this formula? 3 H2SO4 + Ca3(PO4)2 + 6 H2O ↔ 2 H3PO4 + 3 CaSO4.2H2O
Sensei Posted October 24, 2013 Posted October 24, 2013 (edited) 10.00 mL aliquot of a triprotic acid is reacted with 27.42 mL 0.168M KOH solution. Determine the molar mass of the acid. I'm not sure how can I find the mass of the acid, because I don't see anything mass-related to the acid. Which triprotic acids did you have at school? Edited October 24, 2013 by Sensei
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