Widdekind Posted July 26, 2013 Share Posted July 26, 2013 is fire opaque, to EM radiation ? can you project a laser-pointer, through the flame, of (say) some cigarette lighter, or a candle ? http://www.astro.princeton.edu/~burrows/classes/514/opac.2.ps As a thought experiment, if the cores of big bright blue super-massive stars are ~1 g/cm3, ~100MK, then the Kramers' Opacity implies a mean-free-path of ~10-100m... so if you could somehow bury yourself inside the center of some super-massive star, then w/ some sort of super-dark star-glasses you could see through the star, like fog on a football field, from post to post are those numbers accurate, for said supermassive stars ? Link to comment Share on other sites More sharing options...
Enthalpy Posted July 27, 2013 Share Posted July 27, 2013 The flame of my propane or butane lighter is very transparent to the red light of my laser pointer. No perceivable difference at the laser's spot. Nor do I see any spot from the laser's light on the flame. When I had protected a thin sheet of copper from a blowtorch by having water on the other side, the transferred power density was compatible with thermal radiation from acetylene+oxygen, but maybe the transfer was by contact after all. Or the hotter flame is more opaque. Link to comment Share on other sites More sharing options...
swansont Posted July 28, 2013 Share Posted July 28, 2013 It's possible that because it's a plasma, it will attenuate light more readily than a transparent gas would. But to ask whether it's opaque is a poorly-formulated question, because it's not a yes or no answer; it would depend on the thickness of the flame. Link to comment Share on other sites More sharing options...
Widdekind Posted July 28, 2013 Author Share Posted July 28, 2013 http://www.physicsforums.com/showthread.php?t=203289&page=3 fire = "semi-plasma", ionization % = PPB if fire was 100% ionized, then the equations would imply perceivable opacity... but the attenuation distance [math]\equiv 1/\rho \kappa \propto 1/\rho^2[/math] so PPB => km's to attenuate i tried flashlight + match => no shadow from flame, no obscuration thru the flame from flashlight Link to comment Share on other sites More sharing options...
John Cuthber Posted July 28, 2013 Share Posted July 28, 2013 A candle flame glows because it has a lot of hot soot in it. That soot will absorb some light (and re emit it). How much will depend on how big and how sooty the flame is. A quick experiment showed that the attenuation was small with a common household candle flame. Nothing to do with stars. Link to comment Share on other sites More sharing options...
Widdekind Posted July 28, 2013 Author Share Posted July 28, 2013 jet-fighter exhaust is still "too cold" to be highly ionized, and so still presents little opacity: http://community.warplanes.com/wp-content/uploads/2010/06/Lockheed-F-35-Lightning-IIside.jpg i think the same is sayable, for space shuttle thrusters, through which one can see the other in-side surface of the nozzle what would be least unlike stars, would be ion thrusters... perhaps people have ascertained the opacity of ion-thruster-exhaust streams ? Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now