Endercreeper01 Posted August 13, 2013 Posted August 13, 2013 The swartzchild metric gab=-r^4sin^2θ. Why doesn't this have to do with mass?
timo Posted August 13, 2013 Posted August 13, 2013 Not sure what "gab" is supposed to be, but what you posted seems like a single entry of the Schwarzschild metric, at best. The Schwarzschild metric is a tensor (written in particular coordinates), and some of its entries do depend on the mass.
Endercreeper01 Posted August 13, 2013 Author Posted August 13, 2013 (edited) Not sure what "gab" is supposed to be, but what you posted seems like a single entry of the Schwarzschild metric, at best. The Schwarzschild metric is a tensor (written in particular coordinates), and some of its entries do depend on the mass. gab is the meric tensor Edited August 13, 2013 by Endercreeper01
imatfaal Posted August 13, 2013 Posted August 13, 2013 [latex]g_{ab} = \left( \begin{matrix}-(1-2M/r) & 0 & 0 & 0 \\0 & (1-2M/r)^{-1} & 0 & 0 \\0 & 0 & r^2 & 0\\0 & 0 & 0 & r^2sin^2\theta \end{matrix} \right)[/latex] It is slightly more complicated than you first posted 1
Endercreeper01 Posted August 13, 2013 Author Posted August 13, 2013 the Swartzchild metric (using spherical coordinates are t, r, Θ, Φ) ds2=(1-2GM/rc2)dt2- (1-2GM/rc2)-1dr2-r2(dΘ2+r2sin2ΘdΦ). The metric tensor, gab=ds2/Σdxadxb. If you work everything out, then it becomes -r4sin2θ [latex]g_{ab} = \left( \begin{matrix}-(1-2M/r) & 0 & 0 & 0 \\0 & (1-2M/r)^{-1} & 0 & 0 \\0 & 0 & r^2 & 0\\0 & 0 & 0 & r^2sin^2\theta \end{matrix} \right)[/latex] It is slightly more complicated than you first posted (1-m/r) and (1-m/r)-1 cancel out and make -1, and the other part becomes r4sin2θ and so it all becomes -r4sin2θ -1
imatfaal Posted August 13, 2013 Posted August 13, 2013 Do you know what a matrix and/or a tensor are? http://en.wikipedia.org/wiki/Tensor you wrote this ds2=(1-2GM/rc2)dt2- (1-2GM/rc2)-1dr2-r2(dΘ2+r2sin2ΘdΦ) that is the flat space limit which shows we get agreement with newtonian gravitation - although I think you are missing a c^2 from the first part. you can think of it - in a hazy way - of multiplying through that tensor and each section is multiplied by a different factor c^2dt^2, dr^2 dphi^2 and dtheta^2. what it actually is, i hope, is a line element; which is the summation of products of the tensor and four coordinate vectors (phi, theta, radius, and time*c^2) giving the square of the arc length 1
Endercreeper01 Posted August 13, 2013 Author Posted August 13, 2013 Do you know what a matrix and/or a tensor are? http://en.wikipedia.org/wiki/Tensor you wrote this ds2=(1-2GM/rc2)dt2- (1-2GM/rc2)-1dr2-r2(dΘ2+r2sin2ΘdΦ) that is the flat space limit which shows we get agreement with newtonian gravitation - although I think you are missing a c^2 from the first part. you can think of it - in a hazy way - of multiplying through that tensor and each section is multiplied by a different factor c^2dt^2, dr^2 dphi^2 and dtheta^2. what it actually is, i hope, is a line element; which is the summation of products of the tensor and four coordinate vectors (phi, theta, radius, and time*c^2) giving the square of the arc length then how would you calculate the determinant of a 4x4 matrix? and yes, I do and it is actually the swartzchild metric: Schwarzschild metric[edit source | edit]Besides the flat space metric the most important metric in general relativity is the Schwarzschild metric which can be given in one set of local coordinates by -1
xyzt Posted August 13, 2013 Posted August 13, 2013 the Swartzchild metric (using spherical coordinates are t, r, Θ, Φ) ds2=(1-2GM/rc2)dt2- (1-2GM/rc2)-1dr2-r2(dΘ2+r2sin2ΘdΦ). The metric tensor, gab=ds2/Σdxadxb. If you work everything out, then it becomes -r4sin2θ (1-m/r) and (1-m/r)-1 cancel out and make -1, and the other part becomes r4sin2θ and so it all becomes -r4sin2θ Nonsense, you are confusing a matrix with its determinant. 1
imatfaal Posted August 13, 2013 Posted August 13, 2013 agree with xyzt - you seem to be thinking a matrix is merely its determinant. What you have is the line element - which is the distance along an arc squared. Your second equation is exactly the same as the first just represented in terms of solid angle rather than azimuth and inclination. If you really do understand matrices and tensors - then here is a page that describes line elements which is what you are getting with your ds^2 equations http://en.wikipedia.org/wiki/Line_element 1
Endercreeper01 Posted August 13, 2013 Author Posted August 13, 2013 Schwarzschild metric[edit source | edit] Besides the flat space metric the most important metric in general relativity is the Schwarzschild metric which can be given in one set of local coordinates by where from Wikipedia agree with xyzt - you seem to be thinking a matrix is merely its determinant. What you have is the line element - which is the distance along an arc squared. Your second equation is exactly the same as the first just represented in terms of solid angle rather than azimuth and inclination. If you really do understand matrices and tensors - then here is a page that describes line elements which is what you are getting with your ds^2 equations http://en.wikipedia.org/wiki/Line_element oh
Widdekind Posted September 5, 2013 Posted September 5, 2013 the exterior Schwarzschild metric is "four-volume preserving", i.e. space stretches, but time compresses, such that (c dt) dx dy dz = [math](c dt) r^2 dr sin(\theta) d\theta d\phi[/math] = constant trying to take the Trace or determinant, and observing cancelations of crucial coefficients, is essentially the same, as noting that the warping of space-time about the body is "four-volume preserving", space stretches, but time "thins out", preserving the over-all (four) volume, a little like a piece of putty stretching in one dimension, but thinning out in orthogonal directions, preserving the overall volume of putty
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