Semjase Posted October 11, 2013 Posted October 11, 2013 I've found an exact equation for e without pi e=(cos(1/2)+i*sin(1/2))^(2/i) does this mean that e is not a transcendental number?
ajb Posted October 11, 2013 Posted October 11, 2013 does this mean that e is not a transcendental number? No, we have proofs that e is transcendental. Having a closed expression that like, which is correct, does not change these proofs.
Unity+ Posted October 14, 2013 Posted October 14, 2013 You are pretty much just isolating e from the equation.
imatfaal Posted October 14, 2013 Posted October 14, 2013 You are pretty much just isolating e from the equation. You're pretty ,much right - but the above is a bit of a over-complicated cosx+isinx = e^ix cos1/2+isin1/2 = e^(i/2) (e^(i/2))^(2/i)=e
HalfWit Posted October 15, 2013 Posted October 15, 2013 I've found an exact equation for e without pi e=(cos(1/2)+i*sin(1/2))^(2/i) does this mean that e is not a transcendental number? If you find a polynomial with rational coefficients that has e as a zero, then e would not be transcendental. That's the definition.
daniton Posted October 15, 2013 Posted October 15, 2013 Herein the definition of transcendental number.... en.wikipedia.org/wiki/Transcendental_number Now u know the definition... So, your formula doesn't proof whether it is transcendent or not.
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