calbiterol Posted February 6, 2005 Posted February 6, 2005 Given the following situation: A clear, colorless liquid is contained within a double-parabolic mirror that is constructed in such a way that anything placed inside will be reproduced as a virtual image above the two parabolic mirrors, AND the liquid is excited by an ultraviolet laser and, as a result, fluoresces... Will the virtual image be distorted because of the liquid? In other words, will the liquid bend the light emitted by the excited particles?
swansont Posted February 6, 2005 Posted February 6, 2005 The light will bend when it leaves the liquid, if not travelling perpendicular to the interface, due to refraction.
calbiterol Posted February 6, 2005 Author Posted February 6, 2005 The interface being the surface of the liquid?
swansont Posted February 6, 2005 Posted February 6, 2005 The interface being the surface of the liquid? Yes, or where it hits the container, if it's in a container.
calbiterol Posted February 6, 2005 Author Posted February 6, 2005 Is there any way to determine how much the virtual image would be distorted? (Is this the index of refraction that I remember hearing about somewhere?) Better yet, is there any way to bend it back? Or to prevent refraction?
calbiterol Posted February 15, 2005 Author Posted February 15, 2005 *Bump* Thanks for all the help, but I'm still "in the dark."
5614 Posted February 15, 2005 Posted February 15, 2005 Is there any way to determine how much the virtual image would be distorted? to calculate the refraction use snell's law: http://en.wikipedia.org/wiki/Snells_law but is that what you were asking for? Better yet, is there any way to bend it back? Or to prevent refraction? you cannot stop refraction. when light moves between two mediums with different densities it's wavelength increase/decreases but its frequency remains constant resulting in a varying velocity, this causes refraction, when light moves between two mediums with different density (or different refractive index) refraction occurs, you cannot stop that.
calbiterol Posted February 15, 2005 Author Posted February 15, 2005 Does that mean that the closer the densities, the less refraction that occurs?
5614 Posted February 15, 2005 Posted February 15, 2005 Does that mean that the closer the densities, the less refraction that occurs? Yes I would have thought so. Look at Snell's law, see the n1 and n2 in the equation, that refers to the refractive indicies involved.
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