wanted90 Posted October 15, 2013 Posted October 15, 2013 Hi why in this question we did not convert the unit of temperature to kelvin ? Aluminum has A specific heat of 0.902 J/gm C . How much heat is lost when a piece of aluminum with a mass of 23.984 gm cools from a temperature of 415.0 C to a temperature of 22.0 ? the answer is : Q = m Cp X delta T =23.984 X 0.902 X 22 - 415 = -8500 J
swansont Posted October 15, 2013 Posted October 15, 2013 What is the relationship between ºC and K? And what happens with that relationship when you take a temperature difference (delta T)?
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now