Kramer Posted November 16, 2013 Posted November 16, 2013 NATURE’S CONSTANTS OR KRAMER’S “FUDGE “?! IConstant of space potential inside Particle.---Ux*rx = ( e*e / ( 4*pi*ε0 *e ) ) = 1.439964393-*10^-9 V*mUx*rx = ( h*C*α ) / ( 2*pi*e) = 1.439964393-*10^-9 V*m Ux*rx = G*M^2 / e = 1.439964394-*10^-9 V*m Ux*rx = M*R*C^2 / e = 1.439964393-*10^-9 V*m Ux*rx = ( C^2 *R / sqrtG )^2 / e = 1.439964393-*10^-9 V*m ( rx = equal Compton radius )M (usp) = e / (4*pi*ε0*G) ^0.5 = 1.859389987*10^-9 Kg.R (usp) = e / ((4*pi*ε0 / G C^4)^0.5 = 1.38054385410^-36 m ExampleUme = ( 1.439964393*10^-9 ) / ( 2.8170401*10^-15) = 510998.9364 V. 2Constant of Potential in loop of Particle.--- ( For those that hate radius )Ux*λx = 1.23984186*10^-6 V*m ( λx = Compton wave-length ) ExampleUtau = (1.23984186*10^-6) / (0.6977431*10^-15) = 1776931730 V. 3Constant of Energy of Particle.---Ex = eUx = e*((1. 439964393*10^-9) / rx) e*V Ex = eUx = e * ( ( 1. 23984186*10^-6) / λx ) e*VEx = Ux*e = ( 2.307077057*10^-28) / rx joul orEx = Ux*e = ( 1.986445444*10*-25 ) / λx joul Example:Emuon = (1.986445444*10*-25) / ( 11.7344419735*10*-15) = 1.692833327”10^-11 joul orEmuon = ( 1.43984186^10^-6 ) / ( 11.7344419735*10^-15) = 105658357.1 e*V 4 CURRENT INSDIDE THE PARTICLE I = e * fx = e * (C*α / (2*pi*rx) = (5.578488868*10^-14) / rx A. 0rI = e * fx = ( e C) / λx = (4.80320419910^-11) / λxExample:Ime = (5.578488868*10^-14) / re =19.79633507 A orIme = (4.80320419910*!0^-11) / λe = 19.79633303 A 5 RESISTANCERx = Ux / Ix = 25.812,80392 ohm for radius rxRx = Ux / Ix = 25.812,80763 ohm for λx
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now