Are standing waves = to " a regular distance"?

[Iwonderaboutthings]

Are standing waves = to " a regular distance"?

 

Or does this only apply to QM?

 

The reason I ask is because of how a typical distance in the physical real world " also" applies to time.

Time I mean the speed of light, and "typical distance" I mean " example" from your house to your job.

Yes I know about atomic clocks and time dilation.

 

Not sure if c is applicable to " ordinary time though" as in 12: 40 pm, 1:20 am and so fourth.

 

Distance from x to dx, is this another way of describing what I am asking?

 

The way I am thinking is that c " time" which does not exist in this dimension being constant in the known universe must be = to " any distance, vectors and etc that describe time including waves and standing waves. These must be obsolete forms do to Newtonian Mechanics.

 

However, if this is the case, then photons, " mass-less" particles must be something else other than what we know them as, because of their connection to time and distance.

 

I truly believe that photons " do not exist as distance does no exist at all because of the later mentioned.

I may be wrong though and need more clarity on this distance and c relation.

 

 

However, c is a 2d representation " only" with no " volume and or pressure relation to G it appears.

Where G most likely is a separate case in this all together.

 

This being said, then E=mc squared is incorrect??????????

 

 

Remember: in the physical real world " does this apply or is this only valid for QM?

 

But it is rather confusing because to me distance is distance because its relation to time which is c.

Then you have G that makes things move rotate, have mass. This is going to be an interesting topic!

Edited November 17, 2013 by Iwonderaboutthings