sidharath Posted December 2, 2013 Share Posted December 2, 2013 when photon splits into positron and electron .the pair produced is expected to be associated with gravitational field which indicates that in addition to electromagnetic field photon is also carrier of gravitational field Link to comment Share on other sites More sharing options...
swansont Posted December 2, 2013 Share Posted December 2, 2013 Photons exert gravity but are not carriers of the gravitational field. This is easily demonstrated, as one can shield photons and electromagnetic interactions but not gravity. Link to comment Share on other sites More sharing options...
Enthalpy Posted December 2, 2013 Share Posted December 2, 2013 Energy, including photons, creates gravitation as well. The conservation of rest mass +energy implies that the resulting gravitation field doesn't change by the event. Swansont, apologies for paraphrasing you. Link to comment Share on other sites More sharing options...
sidharath Posted December 5, 2013 Author Share Posted December 5, 2013 if photon is associated with gravity it leads to the conclusion that photon is hybrid of two types of highly unstable particles where one is associated with pure electromagnetic field while other is carrier of pure gravity. The particles are named by me as electromagnaton and mattenergon.These particles exist in combined state only.Considering the novel nature of photon the properties of photon can be easily understood and photon is no longer an enigma as it once was was to Einstern Link to comment Share on other sites More sharing options...
sheever Posted December 5, 2013 Share Posted December 5, 2013 Good post and answers. Thanks Photons exert gravity but are not carriers of the gravitational field. This is easily demonstrated, as one can shield photons and electromagnetic interactions but not gravity. Look for photoelectric effect. The electromagnetism and charge is the key, great post Link to comment Share on other sites More sharing options...
decraig Posted December 21, 2013 Share Posted December 21, 2013 (edited) dS/dA=0 David Hilbert solved the vacuum solution of general relativity. I haven't bothered to solve for spatial curvature due to electromagnetism. However Hilbert points the way. Over all possible 4-volumes of spacetime [math]\int F^*F[/math] is minimal in vacuum with respect to the electromagnetic vector potential. F is the Faraday tensor with lower indices. *F is the Hodge dual of the Faraday tensor. (^), is the wedge product operator--reference Grassmann algebra and the exterior calculus. The result is an untested conclusion of general relativity. I don't know what "carrier of gravitational field" means. Edited December 21, 2013 by decraig Link to comment Share on other sites More sharing options...
imatfaal Posted December 21, 2013 Share Posted December 21, 2013 [latex]\int F \wedge * F[/latex] Your latex is a bit wonky - you didn't have a wedge operator in your expression; it's \wedge btw Link to comment Share on other sites More sharing options...
ajb Posted December 21, 2013 Share Posted December 21, 2013 I haven't bothered to solve for spatial curvature due to electromagnetism. We have Einstein-Maxwell theory and there are classes of exact solutions here as well as numerical solutions that have been found. I have no idea about the experimental verification of this theory as for the most part we can comfortably consider EM on a curved background in astrophysics. Link to comment Share on other sites More sharing options...
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