Sup Man Posted February 15, 2005 Share Posted February 15, 2005 Not relevant... read below. Link to comment Share on other sites More sharing options...
Sup Man Posted February 15, 2005 Author Share Posted February 15, 2005 bump. Thanks! Link to comment Share on other sites More sharing options...
mezarashi Posted February 15, 2005 Share Posted February 15, 2005 Sounds interesting, though I don't quite see the picture of what's happening and the definition of "h". I'd understand that the wave propagation here involves waves that are of the pendulum's natural oscillating frequency. Link to comment Share on other sites More sharing options...
swansont Posted February 15, 2005 Share Posted February 15, 2005 Do you have an equation that relates the wave properties to the tension in the string? and you had to bump the thread because nobody answered it in 45 minutes? Link to comment Share on other sites More sharing options...
Sup Man Posted February 15, 2005 Author Share Posted February 15, 2005 Figured it out. Link to comment Share on other sites More sharing options...
J.C.MacSwell Posted February 15, 2005 Share Posted February 15, 2005 Yes' date=' wave speed = sqrt(tension/linear density) However, isn't the tension 0? I mean it is just the rope hanging. Here is the exact wording of the question. "A uniform cord of length L and mass m is hung vertically from a support. A) Show that the speed of transverse waves in this cord is sqrt(gh), where h is the height above the lower end. B) How long does it take for a pulse to travel upward from one end to the other?[/quote'] The tension would increase linearly from the bottom up. Link to comment Share on other sites More sharing options...
Sup Man Posted February 15, 2005 Author Share Posted February 15, 2005 Got it. Link to comment Share on other sites More sharing options...
swansont Posted February 16, 2005 Share Posted February 16, 2005 JC is assuming the string has a non-negligible mass. But since it's not given, let's approximate it as zero. The mass m feels a force mg down, and yet it's not accelerating. What's holding it up? Link to comment Share on other sites More sharing options...
Sup Man Posted February 16, 2005 Author Share Posted February 16, 2005 Problem finished. Link to comment Share on other sites More sharing options...
swansont Posted February 16, 2005 Share Posted February 16, 2005 there is no mass hanging... m = mass of the cord. The mass is not negligible. Then JC was correct; the tension will increase down the cord. Link to comment Share on other sites More sharing options...
scm007 Posted February 16, 2005 Share Posted February 16, 2005 What is this? Link to comment Share on other sites More sharing options...
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