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Posted (edited)

hello i need help in solving this
Q)If the speed of a vehicle increases by 2 m/s,its kinetic energy is doubled,then original speed of the vehicle is
a)(sqrt of 2 )+1 m/s

b)2(sqrt of 2 -1)m/s

c)2(sqrt of 2 + 1 )m/s

d)sqrt of 2 (sqrt of 2 + 1)m/s

sqrt is square root of

please help me out

Thnx in advance

Edited by Jay Sharma
Posted

there is no equation given for K.E

 

What is classical Kinetic Energy equation that you learn in the first class of physics?

Posted (edited)
so i got v=2 so how do i find the correct option sad.png

 

 

It's not the right answer.

 

I entered it to OpenOffice

A column is velocity

B column is K.E. with v

C column is. K.E. with v+2

D column is C/2

 

 

See where they're crossing..

 

post-100882-0-19379000-1391799829_thumb.png

 

You should not guess, but calculate..

 

v^2-4*v-4=0

 

Edited by Sensei
Posted

 

It's not the right answer.

 

I entered it to OpenOffice

A column is velocity

B column is K.E. with v

C column is. K.E. with v+2

D column is C/2

attachicon.gifKinetic Energy table.png

 

See where they're crossing..

 

You should not guess, but calculate..

 

v^2-4*v-4=0

 

oh sorry i had taven -4 as +4 sorry for that

thank you sensai for your help

i found that the option c (c)2(sqrt of 2 + 1 )m/s)is correct please just crosscheck it once please

thank you please help me in my others questions in my other posts please

Posted

V equal approximately 4.828 is the answer.

 

2* (sqrt(2)+1) = ~4.828

is that means i m right

if yes then please help me in my other posts too

if no then also help me

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