projectile 2

[gwiyomi17]

i have no idea how to start this

[studiot]

So the projectile travels a horizontal distance = (50 + x) where x is to be determined ( and a vertical distance of y, also to be determined).

 

Have a look back at your first projectile question and draw a sketch similar to my one there and then look at the equations I started with.

 

Can you find a pair of simultaneous equations from this that you can solve for x and y?

[imatfaal]

Further to Studiot - set up your rectangular coordinate system with origin at the point of projectile launch. You then can work out two equations y in terms of x (ie vertical displacement in terms of horizontatal) - one equation tracks the projectile (and is thus gonna have an x^2 term) the other is the ramp and linear (and will thus only have an x terms plus constant). Be sure to get your pluses and minuses sorted! It's a bit messy but doable.

[gwiyomi17]

like this?

 

Edited February 13, 2014 by gwiyomi17

[studiot]

The horizontal distance between A and the impact point is x, not 50+x.

It is 50+x from the launch point to the impact point.

 

I get

 

50+x = 98.29825t horizontal flight

 

y = xtan42 = 0.9x Triangle

 

y = 68.829t - 4.9t² vertical flight

 

Three equations, three unknowns.

 

Easy solution over to you

[gwiyomi17]

AAAHH YESS!!

x+50 is the whole range

 

i get it! thank soo muchhh!! your a lifesaver !

[studiot]

 

your a lifesaver !

 

When certain individuals are firing on the range the safest place to stand is by the target!