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Posted

how did you arrive at this conclusion?

did you use a particular algorithm?

what can you use it for?

I used some maths

 

 

The Earth's spin is 1,038 miles per hour

 

 

An hour is 3600 so 1038/3600 = 2.888

 

 

2.8888 x 86,400 = 249120 miles

 

 

Earth,s circumference = 24,859.82 miles

 

 

it is 2.88833333 so slightly off.

I used some maths

 

The Earth's spin is 1,038 miles per hour

 

 

An hour is 3600 so 1038/3600 = 2.888

 

 

2.8888 x 86,400 = 249120 miles

 

 

Earth,s circumference = 24,859.82 miles

 

 

it is 2.88833333 so slightly off.

 

I get the earth's circumference as 24912 miles

Posted (edited)

so, by your math, a stationary man standing in front of the earth would watch 2.888 miles go by each second.

Edited by davidivad
Posted

so, by your math, a stationary man standing in front of the earth would watch 2.888 miles go by each second.

I should of used a sidereal day and would have got the other result.

 

 

In answer to your question , yes if the observer was watching a fixed point.

 

 

He would see 2.888 miles pass using a solar day timing, and on a sidereal timing.

 

2.883333m x 86164s = 24860 miles

He only see's 2.88 mile passing by of the earth, he does not move, you can work out the other planets and they should fit also.

Posted

another one...

curious.

 

I do apologise, it has sort of left me again for a minute.

 

I can not think the maths now, it came to me then went, I will regroup and get my head around the maths again,

 

 

My apologies, I will be back and explain where my conclusion came from, I have lost my own idea I had.

Posted (edited)

Actually, 1 second is equal to 186,282 miles.

The speed of light ''C'' came later than the original definition of a second.

 

The origin of the second is the issue, a solar year, and now seemingly the second is associated with distance, although time still moves in a stationary position.

Mars spin velocity,

 

539.487 mph

 

 

mars equator circumference 13,300 miles

 

 

 

13,300/539.487= 24.64

 

 

24.64x3600=88704 would that be the correct amount of seconds in a Martian day?

 

 

I get Mars as 0.14 m/s

13292.95968

 

That gives this circumference I fiqure solar day?

Edited by Relative
Posted

so what are you planning to do with this idea?

I have no idea, just thought I would share it, and maybe create a universal time, using some other factors.

 

 

Not sure to be honest I am just a thoughtful mind.

Posted

never stop asking questions is my thought.

a universal time would be a great contribution.

any one know at what distance and velocity we are seeing the redshift objects moving away in our expanding universe?

Posted

any one know at what distance and velocity we are seeing the redshift objects moving away in our expanding universe?

A minimum of 200 million lys, and velocity increases with distance.

Posted

A minimum of 200 million lys, and velocity increases with distance.

That rules out that out then we can not reverse the distance to a central point.

Posted

I used some maths

The Earth's spin is 1,038 miles per hour

 

Only at the equator. I estimate it is about half that where I live. And zero at the North Pole.

 

Is that significant? I'm not sure, because I don't know what you think the significance of 2.88 miles per second is.

The origin of the second is the issue, a solar year, and now seemingly the second is associated with distance, although time still moves in a stationary position.

 

The second has nothing to do with distance. It used to be defined in terms of the length of a day. But is no longer.

 

 

24.64x3600=88704 would that be the correct amount of seconds in a Martian day?

 

The Mars day is about 1 hour 40 minutes or 88,775.24409 seconds

Posted (edited)

he is clearly having fun with numbers.

you have to start somewhere.

discovery is a better tool than failure.

 



 

Edited by davidivad
Posted (edited)
The second has nothing to do with distance. It used to be defined in terms of the length of a day. But is no longer.

 

 

Originally a solar day was based on one rotation of the Earth compared to the Sun. From point A , 360 degrees, which its origin,

 

could of been measured as a unit of Distance. 24 hours divided into seconds, divided by circumference of the Earth, which gives 2.88333 mile per second.

 

 

1 second of clock time , equal to the distance of 2.888333 mile travelled in rotation.

 

 

Because of fluctuations in the rotation speed, it was decided to use the atomic clock and the caesium 133 etc.

 

 

However, after study, I have found that the atomic clocks second, was chosen/invented, and has close as possible to an original clock second.

 

 

So technically science just changed the colour . The second on an atomic clock is the same has a second on any clock.

 

 

So 2.883333 mile is still one second, dictated my man.

''The Mars day is about 1 hour 40 minutes or 88,775.24409 seconds''

 

solar or sidereal?

''Only at the equator. I estimate it is about half that where I live. And zero at the North Pole.

Is that significant? I'm not sure, because I don't know what you think the significance of 2.88 miles per second is.''

Well, you need zero, you can not have time measured by distance, and time and distance setting the size of the other planets by the look of it.

Edited by Relative

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