SpaceLight Posted April 7, 2014 Posted April 7, 2014 Presently, two things I need clarity on, please.Thing 1:I found this on youtube I organized it in the following and hope it's good for arriving at fair approximations of torque and rpm...T = I x alpha = F x r x sin(theta):By example...A rotor Mass of 100 kg,'r' of 2 meters,A force of 75 Newtons,point of force at a 90 degree angle.First filling in T = F x r x sin(theta), as such:T = 75 N x 2 m x sin(90) = 150 N*mT = 150 N*mNext, add the other part of the equation, T = I x alpha; I = 1/2Mr^2, hence:T = 150 N*m = 1/2M x r^2 x alphaResolved progressively...T = 150 N*m = 50 kg x 2^2 x alphaT = 150 N*m = 50 kg x 4 x alphaT = 150 N*m = 200 x alphaNext, for alpha:alpha = 150 divided by 200 = .75 rad/s^2Next, convert .75 rad/s^2 to RPM using this equation:([rad/s]/6.28318530718) x 60 = RPM(Note: 6.28318530718 was Pi x 2, I just filled it in....)Solved progressively...([.75 rad/s]/6.28318530718) x 60 = RPM.11936620731891365 x 60 = RPM.11936620731891365 x 60 = 7.161972439134819 RPM.75 rad/s^2 = 7.161972439134819 RPMCorrect?Thing 2: Please refer to attachment "thing 2".The only known variables:1) One angle (at the location depicted in the diagram).2) Distance between A & B.Objective: Find line 3 (the dotted line) given the two known variables; line 3 needs to be perpendicular to line 2. Note: The one known angle is not 90 degrees.If you could write the solution out simply enough with an example, that would be helpful.Sincerely grateful for your guidance. Thing2.bmp
imatfaal Posted April 7, 2014 Posted April 7, 2014 ! Moderator Note Homework Help Rules A simple reminder to all: this is the "Homework Help" forum, not the "Homework Answers" forum. We will not do your work for you, only point you in the right direction. Posts that do give the answers may be removed. So SpaceLight would you explain where you have got to in solving this problem and what has stopped your progress - hopefully members can then help you to overcome your difficulties yourself.
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