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We completed a redox titration of Iodine
(formed from 1M Potassium Iodide (KI), 0.1M Potassium Iodate (KIO3) and excess Hydrochloric acid (KCl)


against Sodium thiosufate (Nas2O3)

It took 25.8cm3 of 0.1 M Nas2O3 to get rid of the formed Iodine.

The question asks:

Use the equation below to calculate the amount of iodide ions that reacts with each mole of iodate ions in aqueous solution

2S2O32- (aq)+ I2 (aq) rarrow.png 2I- (aq) + S4O62-(aq)

and determine the concentration of iodide ions in moldm-3

I am not sure what this is asking me! Do I need to calculate how the Iodine is originally formed?
I am really stuck on this one! Please help.

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