raja.mugavai Posted July 30, 2014 Posted July 30, 2014 A'B'C'+A'BC'+A'BC+ABC How to simplify the above expression.... Kindly help me...
CaptainPanic Posted July 30, 2014 Posted July 30, 2014 Please show us what you have tried so far to get to an answer. Also, a little more introduction might be helpful. What do these letters represent? Functions? Matrices? (I get a feeling it is linear algebra, but it might be useful to clarify that). A reminder: this is the "Homework Help" forum, not the "Homework Answers" forum. We will not do your work for you, only point you in the right direction. (Posts that do give the answers may be removed.)
raja.mugavai Posted July 30, 2014 Author Posted July 30, 2014 Please show us what you have tried so far to get to an answer. Also, a little more introduction might be helpful. What do these letters represent? Functions? Matrices? (I get a feeling it is linear algebra, but it might be useful to clarify that). A reminder: this is the "Homework Help" forum, not the "Homework Answers" forum. We will not do your work for you, only point you in the right direction. (Posts that do give the answers may be removed.) I have one doubt in this boolean expression. That line is A' (C'+b) (C'+C) + AB'C'
studiot Posted July 30, 2014 Posted July 30, 2014 See post#4 here http://www.scienceforums.net/topic/84417-boolean-equation-truth-table/
dickiejohnny Posted February 25, 2015 Posted February 25, 2015 (edited) The url deleted is providing a free tool to simplify any kind of logical function. The answer is A'B'C'+A'BC'+A'BC+ABC=A'C'+BC A'B'C'+A'BC'+A'BC+AB'C'=A'B+B'C' The url deleted is providing a free tool to simplify any kind of logical function. The answer is A'B'C'+A'BC'+A'BC+ABC=A'C'+BC A'B'C'+A'BC'+A'BC+AB'C'=A'B+B'C' Edited February 25, 2015 by swansont advertising
fiveworlds Posted February 25, 2015 Posted February 25, 2015 (edited) C'+C=On with an and gate means it makes no difference in the circuit A' (C'+b) (C'+C) + AB'C' From the boolean identity laws 1A=A A' (C'+b) (C'+C)=A' (C'+b) 1=1A' (C'+b) =A' (C'+b) Edited February 25, 2015 by fiveworlds
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