gwiyomi17 Posted September 20, 2014 Share Posted September 20, 2014 Hi I am doing a project about analyzing different trends on the periodic table using some data of the first 20 elements. I already graphed their data and answered all of the questions that I'm required to answer, but I'm stuck with this question because I'm not sure how to do it. Can someone help me? Thanks. Here is the question: Using graphical method or any other, estimate the atomic radius and predict a first ionization energy for Cesium. Link to comment Share on other sites More sharing options...
Essay Posted September 20, 2014 Share Posted September 20, 2014 So do you know about a relationship between radius and ionization energy, or can you see such in your graphs or trends? What trends have you identified so far? ~ Link to comment Share on other sites More sharing options...
gwiyomi17 Posted September 20, 2014 Author Share Posted September 20, 2014 For the atomic radii, it increases as you go down the group and decreases across the periodic table. The highest atomic radii(peaks of my graph) is found in group 1A while the lowest atomic radii (troughs of my graph) is found in group 8A (noble gases). This is vice versa with the ionization energy. Link to comment Share on other sites More sharing options...
Essay Posted September 20, 2014 Share Posted September 20, 2014 So if size increases as you go down the group, can Cs size be predicted by the trend of sizes, in the Cs group, above Cs? ~ 1 Link to comment Share on other sites More sharing options...
gwiyomi17 Posted September 20, 2014 Author Share Posted September 20, 2014 (edited) yeah, Cs will be larger than the ones above it. Edited September 21, 2014 by gwiyomi17 Link to comment Share on other sites More sharing options...
Essay Posted September 21, 2014 Share Posted September 21, 2014 (edited) ...especially considering the limited (and only roughly accurate) initial data.... That seems like a logical strategy, and a reasonable answer. Can you do the same with ionization energy? ~ Edited September 21, 2014 by Essay Link to comment Share on other sites More sharing options...
gwiyomi17 Posted September 21, 2014 Author Share Posted September 21, 2014 (edited) If it is right, I'll do it with the ionization energy. Thank you for checking it well I don't think it will work for the Ionization energy Li=0.52 Mj.mol-1 Na=0.50 Mj.mol-1 K=0.42 Mj.mol-1 their rates are different :/ Edited September 21, 2014 by gwiyomi17 Link to comment Share on other sites More sharing options...
Essay Posted September 21, 2014 Share Posted September 21, 2014 The change isn't the same, or linear, but there is another trend. It is a curved or nonlinear progression, though depending on how it is estimated, it could be below zero too soon. I'd go with a 'best estimate' and ask questions about if some other strategy could work. I'd like to know about another way to guesstimate this. Good luck ~ Link to comment Share on other sites More sharing options...
studiot Posted September 21, 2014 Share Posted September 21, 2014 (edited) Using graphical method or any other, estimate the atomic radius and predict a first ionization energy for Cesium. So do you know about a relationship between radius and ionization energy Is there one? Your first ionisation graph should look something like this. You should be able to pick out the trend. Edited September 21, 2014 by studiot Link to comment Share on other sites More sharing options...
gwiyomi17 Posted September 21, 2014 Author Share Posted September 21, 2014 yes i got a similar graph, but how can i find the value for the ionization for Cs? Link to comment Share on other sites More sharing options...
studiot Posted September 21, 2014 Share Posted September 21, 2014 (edited) I would draw an averaging line through Li, K and Na and extend it to Cs. My graph shows it would give a better estimate if you could include Rb. The actual value can be looked up on Google or is on my graph for comparison. Edited September 21, 2014 by studiot Link to comment Share on other sites More sharing options...
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