Gamewizard Posted October 1, 2014 Posted October 1, 2014 Hi, I just want to ask if doubling dilutions are the same as serial dilutions ? I have tried researching them but I have got more confused! Thanks in advance
fiveworlds Posted October 1, 2014 Posted October 1, 2014 (edited) Not according to http://www.google.ie/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&cad=rja&uact=8&ved=0CCEQFjAA&url=http%3A%2F%2Fwww.austincc.edu%2Fmlt%2Fclin1%2Fser_SerialDilutions.ppt&ei=JRAsVJD9J-Ke7gbDm4CIBw&usg=AFQjCNEBU8TDlOZ8TJGB7vMxqKOFYNuubw&sig2=vzy24CmRP8BKE4ngwaYteQ&bvm=bv.76477589,d.ZGU . The wiki states that a serial dilution are the stepwise dilution of a substance in solution. Whereas doubling dilutions is the stepwise dilution of the substance in solution by 1/2. So doubling dilutions are a type of serial dilution. The word serial means of or forming a series. So serial dilutions are done in a particular series and everything can be in a series. So any dilution. Edited October 1, 2014 by fiveworlds 1
Wrynn Posted October 3, 2014 Posted October 3, 2014 (edited) Hi, those are not the same: Doubling dilution is a serial dilution effected so that the concentration in each tube of the particular cell, substance, etc. of interest is half that in the preceding tube of the series. Whereas serial dilution is the stepwise dilution of a substance in solution. Usually the dilution factor at each step is constant, resulting in a geometric progression of the concentration in a logaritmic fashion. A ten-fold serial dilution could be 1 M, 0.1 M, 0.01 M, 0.001 M. Edited October 3, 2014 by Wrynn
fiveworlds Posted October 5, 2014 Posted October 5, 2014 (edited) 1 M, 0.1 M, 0.01 M, 0.001 M Which is 1/((10)^a) >> a(0---3) Hi, those are not the same: I did not say they were. Edited October 5, 2014 by fiveworlds
Gamewizard Posted October 29, 2014 Author Posted October 29, 2014 Thank you, I understand the difference between them now.
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