love sersh Posted October 13, 2014 Share Posted October 13, 2014 (edited) I've just met a problem when I differentiated the mass-velocity equation. In m2(c2-v2)=m02c2 because the right one is a constant after differentiation , i got d [ m2(c2-v2) ] = 0 which means c2 d (m2) = d(m2v2) i don't think it makes sense, hope someone can help me point out the wrong step,thanks a lot! Edited October 13, 2014 by love sersh Link to comment Share on other sites More sharing options...
xyzt Posted October 13, 2014 Share Posted October 13, 2014 (edited) I've just met a problem when I differentiated the mass-velocity equation. In m2(c2-v2)=m02c2 You should get [math]2mc^2dm-2m^2vdv-2v^2 mdm=0[/math] or, alternatively: [math]2c^2mdm=d(m^2v^2)[/math] or [math]c^2d(m^2)=d(m^2v^2)[/math] Edited October 13, 2014 by xyzt 1 Link to comment Share on other sites More sharing options...
love sersh Posted October 13, 2014 Author Share Posted October 13, 2014 You should get [math]2mc^2dm-2m^2vdv=0[/math], i.e. [math]c^2dm=0.5md(v^2)[/math] I knew that , but it's the next step ,c2 d (m2) = d(m2v2) , c2 2mdm=2mvdmv , I m just a little confused about the first one Link to comment Share on other sites More sharing options...
xyzt Posted October 13, 2014 Share Posted October 13, 2014 (edited) I knew that , but it's the next step ,c2 d (m2) = d(m2v2) , c2 2mdm=2mvdmv , I m just a little confused about the first one [math]c^2 d(m^2)= d(m^2v^2)[/math] is perfectly correct. Edited October 13, 2014 by xyzt Link to comment Share on other sites More sharing options...
elfmotat Posted October 13, 2014 Share Posted October 13, 2014 Just as a little aside, nobody uses the concept of relativistic mass anymore. It's not very useful and tends to confuse people. Link to comment Share on other sites More sharing options...
love sersh Posted October 13, 2014 Author Share Posted October 13, 2014 Just as a little aside, nobody uses the concept of relativistic mass anymore. It's not very useful and tends to confuse people. so what concept should we use to deal with the prediction of lorentz transformation? [math]c^2 d(m^2)= d(m^2v^2)[/math] is perfectly correct. thanks,i am just not sure about it at first Link to comment Share on other sites More sharing options...
elfmotat Posted October 13, 2014 Share Posted October 13, 2014 so what concept should we use to deal with the prediction of lorentz transformation? Just use rest mass in all of your equations. Link to comment Share on other sites More sharing options...
swansont Posted October 14, 2014 Share Posted October 14, 2014 ! Moderator Note A hijack was split off http://www.scienceforums.net/topic/86060-hijack-from-question-about-sr-derivation/ Discussion on locked threads also split http://www.scienceforums.net/topic/86063-unlocking-a-thread/ Link to comment Share on other sites More sharing options...
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