Nadbuddy Posted November 8, 2014 Share Posted November 8, 2014 Hi forums! Just wanted to start out with a greeting as i'm new to this forum. I'm 14 and i'm in the 9th grade (Swedish school) and we're starting to learn about half-life and radioactivity. I'd really want to know more about it and if anyone knows a way to briefly explain how these two are related to each other and how they work. We haven't gone into it that much and this is why i'm here. Physics and math are my absolute favorite subjects and i want to explore whatever i find within these two subjects deeper and more complicated. This might be much about me but this is to give you an idea of what kind of person i am and how you would be able to explain it to me. All the knowledge we've received are that half-time is the time it takes for an atom to split in half which relates to radioactivity because radioactive decay is when an unstable atom loses energy by discharging ionizing radiation. I interpret it as both are the same thing, i'm not sure if that's correct or not. I am here looking for help. If there are anything you could advice me when it comes to going deeper in physics (from the state where i am now) feel free to tell me, i don't care if its in school or not. Whatever knowledge there are about physics, i'll learn them all. I hope this is not too basic for a forum like this, i really don't know where else to go since talking to the teachers isn't really a good place to look for answers that has nothing to do with school material. (They just don't have the time i guess). Link to comment Share on other sites More sharing options...
Sensei Posted November 8, 2014 Share Posted November 8, 2014 Atoms are not "splitting in half". Half-life is time needed to decay half of amount of atoms. f.e. you have 100 particles of unstable isotope at time t0 then 50 particles at time t1 then 25 particles at time t2 where (t1-t0) = (t2-t1) = half-life time Obviously while unstable isotope amount is decreasing with time, final product isotope is increasing at the same time. You should start from reading about beta decay http://en.wikipedia.org/wiki/Beta_decay Alpha decay http://en.wikipedia.org/wiki/Alpha_decay Proton emission http://en.wikipedia.org/wiki/Proton_emission Neutron emission http://en.wikipedia.org/wiki/Neutron_emission 2 Link to comment Share on other sites More sharing options...
swansont Posted November 8, 2014 Share Posted November 8, 2014 Half-life is time needed to decay half of amount of atoms. f.e. you have 100 particles of unstable isotope at time t0 then 50 particles at time t1 then 25 particles at time t2 where (t1-t0) = (t2-t1) = half-life time One thing to keep in mind, though, is that owing to the statistical/probabilistic nature of decay, the equations will only work well when you have a fairly large number of them. Realistically, Sensei's example should have some additional zeroes on the end of them (e.g. 1,000,00 atoms decaying to 500,000 and then 250,000). If you were actually doing an experiment you'd see significant fluctuations away from the prediction with small numbers. Conceptually though, it's correct. 2 Link to comment Share on other sites More sharing options...
Janus Posted November 8, 2014 Share Posted November 8, 2014 Atoms are generally unstable because of either an imbalance of neutrons and protons in the nucleus or just too many of both for the nucleus to hold on to . The atom can try to remedy this in a couple of ways, One is to eject 2 neutrons and 2 protons as a high speed helium nucleus known as an alpha particle as a way to reduce the number of nucleons. Sometimes the nucleus will emit an electron (known as a beta particle) and in the process a neutron becomes a proton. More rarely, a nucleus will emit a positron (known as a beta+ particle) and a proton becomes a neutron. In any case, the nucleus changes and we end up with a new element. Many times, the new nucleus itself is not stable and you can get a series of nuclei, each decaying into the other until a stable nucleus is reached. There is no way to predict when a particular nucleus will decay, however statistically, if we have a large number of nuclei, we can work out how long it would take for half of them to decay. This is what a Half-life is, it is the time it would take for half of a sample of nuclei to undergo decay to the next nuclei. So, if for example, you had a kilogram of a radioactive isotope with a half-life of 1 day, after 1 day 1/2 kilogram of it would have decayed and you would be left with 1/2 kilogram of the original isotope. After another day 1/2 of that would have decayed, leaving you with 1/4 kg. each subsequent day leaves you with half of what you had the previous day. I hope this helps. Don't worry about asking "basic" questions. Everyone here has been at your level of understanding at one time, and there are a lot who are more then willing to help someone who is eager and willing to learn. 2 Link to comment Share on other sites More sharing options...
Sensei Posted November 9, 2014 Share Posted November 9, 2014 More exotic decay modes are double beta decay minus, and double beta decay plus http://en.wikipedia.org/wiki/Double_beta_decay Electron capture http://en.wikipedia.org/wiki/Electron_capture Double electron capture http://en.wikipedia.org/wiki/Double_electron_capture Isomeric transition http://en.wikipedia.org/wiki/Nuclear_isomer Link to comment Share on other sites More sharing options...
Nadbuddy Posted November 9, 2014 Author Share Posted November 9, 2014 Thanks for the info, i'll be reading all this and i'll come back and see if i've understood it correctly. Link to comment Share on other sites More sharing options...
between3and26characterslon Posted November 11, 2014 Share Posted November 11, 2014 (edited) Hi forums! Just wanted to start out with a greeting as i'm new to this forum. I'm 14 and i'm in the 9th grade (Swedish school) and we're starting to learn about half-life and radioactivity.'t know where else to go since talking to the teachers isn't really a good place to look for answers that has nothing to do with school material. (They just don't have the time i guess). I've put in bold to remind people that you are "14" and "just starting" to learn about these things Very simply if you have a counter that counts the number of radioactive decays per second and it reads say 100 decays per second and you carry on measuring until it reads 50 decays per second and it takes 2 weeks for this to happen you now know the half life is 2 weeks. If you measure for another 2 weeks your counter will read 25 decays per second and 2 weeks after that 12.5 decays per second. Half life is the ammount of time it takes something to become half as radioactive. Be careful not to be confused by what Sensei said Atoms are not "splitting in half". Half-life is time needed to decay half of amount of atoms. f.e. you have 100 particles of unstable isotope at time t0 then 50 particles at time t1 then 25 particles at time t2 That would be ferociously radioactive for anything with a half life of less than several billion years if that were the measure i.e 238 grammes of U238 = 6x1023 atoms, divide by a billion years = 6x1014 decays per year, divide by number of seconds per year = 19,025,875 decays per second EDIT: Also with this definition the rate of decay would be constant 100 clicks at t1, 100 clicks at t2, 100 clicks at t3, until all gone is not half life Edited November 11, 2014 by between3and26characterslon Link to comment Share on other sites More sharing options...
Sensei Posted November 11, 2014 Share Posted November 11, 2014 (edited) That would be ferociously radioactive for anything with a half life of less than several billion years if that were the measure i.e 238 grammes of U238 = 6x1023 atoms, divide by a billion years = 6x1014 decays per year, divide by number of seconds per year = 19,025,875 decays per second Are familiar with function allowing calculate decays per second at all? For U-238 (238 g sample) decays per second will be average 2.136 mln/second. Uranium-238 -> Thorium-234 + alpha + 4.26992 MeV 4.26992 MeV is 6.84*10^-13 J energy. 2.136*10^6 * 6.84*10^-13 J = 1.4608*10^-6 J/s 100,000 times less than LED diode with U=5 V,I=25 mA is consuming energy per second.. Edited November 11, 2014 by Sensei Link to comment Share on other sites More sharing options...
between3and26characterslon Posted November 11, 2014 Share Posted November 11, 2014 Are familiar with function allowing calculate decays per second at all? For U-238 (238 g sample) decays per second will be average 2.136 mln/second. Merely pointing out that the definition you gave of time needed to decay half of amount of atoms would not only be extremely radioactive but the rate of decay would not decrease over time. I thought it was an important distinction that it is not the number of particles you start with but the number of decays you detect Link to comment Share on other sites More sharing options...
Enthalpy Posted November 12, 2014 Share Posted November 12, 2014 Radioactive half-lives span from very long (238U) to extremely short, without a clear lower limit. No worry with Sensei's example of a half-life equal to 1, even less so because he didn't tell the unit. Here's an example of a chart of the nuclides, where the colours indicate the half-life between 10+15s and 10-15s: http://www.nndc.bnl.gov/chart/ Link to comment Share on other sites More sharing options...
swansont Posted November 12, 2014 Share Posted November 12, 2014 Merely pointing out that the definition you gave of time needed to decay half of amount of atoms would not only be extremely radioactive but the rate of decay would not decrease over time. I thought it was an important distinction that it is not the number of particles you start with but the number of decays you detect No unit was given, and of course the decay rate would decrease over time. The decay rate is proportional to the sample size. Further, "highly radioactive" is somewhat subjective, but in that example, even if all 100 atoms decayed in a millisecond, it would still only be 100 decays. A standard unit for activity is the curie (Ci), which is 3.7 x 1010 decays per second. 1 Ci gamma sources give about 1 rem/hour dose at 1 meter, so that's a lot. 1 microcurie, OTOH, would give 9 millirem/year at 1 meter, which is not a large dose. The human body contains radioactive C-14 and K-40 which undergo several thousand decays per second, and you are not a meter away. People are not generally considered highly radioactive. Link to comment Share on other sites More sharing options...
between3and26characterslon Posted November 15, 2014 Share Posted November 15, 2014 Are familiar with function allowing calculate decays per second at all? For U-238 (238 g sample) decays per second will be average 2.136 mln/second. Uranium-238 -> Thorium-234 + alpha + 4.26992 MeV 4.26992 MeV is 6.84*10^-13 J energy. 2.136*10^6 * 6.84*10^-13 J = 1.4608*10^-6 J/s 100,000 times less than LED diode with U=5 V,I=25 mA is consuming energy per second.. Having given it some more thought what you said in you first post makes sense, I don't know, maybe it had been a long day but when I first read your post it looked wrong. Link to comment Share on other sites More sharing options...
Sensei Posted November 15, 2014 Share Posted November 15, 2014 Having given it some more thought what you said in you first post makes sense, I don't know, maybe it had been a long day but when I first read your post it looked wrong. See this old thread http://www.scienceforums.net/topic/83245-a-question-on-radioactive-decay/#entry806204 I am showing how to set up OpenOffice SpreadSheet for decay rate equation. Link to comment Share on other sites More sharing options...
Nadbuddy Posted November 23, 2014 Author Share Posted November 23, 2014 Thank you for all the answers and sorry for the late reply. I've read through most of what you people have linked and said on the thread and i cannot be more thankful. Thank you once again for explaining. Link to comment Share on other sites More sharing options...
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