Velocity of a Neutrino

[DimaMazin]

 

Same as anything else:

[math]\displaystyle m_o c^2 \left(\frac{1}{\sqrt{1-\frac{v^2}{c^2}}} - 1 \right)[/math]

Do you think scientists measure neutrino KE by Joules?

[Strange]

Do you think scientists measure neutrino KE by Joules?

 

 

I don't expect they measure the mass in kg, either. But you can multiply by the appropriate factor to convert to whatever units you want; it doesn't change the equation.

Edited November 21, 2014 by Strange

[swansont]

Do you think scientists measure neutrino KE by Joules?

 

eV is more likely because it's the appropriate scale for atomic/nuclear/particle systems, but ultimately it doesn't matter since the conversion is trivial.

[DimaMazin]

 

 

I don't expect they measure the mass in kg, either. But you can multiply by the appropriate factor to convert to whatever units you want; it doesn't change the equation.

I only have wrongly called energy of rest mass by gravitational energy . Therefore you think I use another equation.

[Strange]

I only have wrongly called energy of rest mass by gravitational energy . Therefore you think I use another equation.

 

No, you were just talking nonsense. Not particularly funny.

[DimaMazin]

 

No, you were just talking nonsense. Not particularly funny.

EK(eV units)=(gamma-1)E₀(eV units) _* 6.24150934_*10¹⁸

E₀ - rest energy

[swansont]

EK(eV units)=(gamma-1)E₀(eV units) _* 6.24150934_*10¹⁸

E₀ - rest energy

 

That won't get you energy in Joules, it will get you an answer in eV²/J. However, this doesn't affect the physics of the problem. So what's the point?

[DimaMazin]

 

That won't get you energy in Joules, it will get you an answer in eV²/J. However, this doesn't affect the physics of the problem. So what's the point?

Yes.

E=gamma_*E₀

EK=E-E₀

EK(eV units)=gamma_*E₀(eV units) - E₀(eV units)=(gamma-1)E₀(eV units)

[Strange]

Yes.

E=gamma_*E₀

EK=E-E₀

EK(eV units)=gamma_*E₀(eV units) - E₀(eV units)=(gamma-1)E₀(eV units)

 

Is there a point to these rather mangled equations?

[swansont]

Yes.

E=gamma_*E₀

EK=E-E₀

EK(eV units)=gamma_*E₀(eV units) - E₀(eV units)=(gamma-1)E₀(eV units)

 

What is the point?

 

While unit consistency is important (e.g. everything here has units of energy) the actual unit system used is a secondary consideration — it does not need to be specified in the equation.

[DimaMazin]

 

Is there a point to these rather mangled equations?

Let's check.

gamma=2

E₀=1eV

then E_total=2eV

and EK=1eV

E₀=EK it's correct when gamma=2