DimaMazin Posted November 21, 2014 Posted November 21, 2014 On 11/21/2014 at 12:48 PM, Strange said: Same as anything else: \displaystyle m_o c^2 \left(\frac{1}{\sqrt{1-\frac{v^2}{c^2}}} - 1 \right) Do you think scientists measure neutrino KE by Joules?
Strange Posted November 21, 2014 Posted November 21, 2014 (edited) On 11/21/2014 at 2:18 PM, DimaMazin said: Do you think scientists measure neutrino KE by Joules? I don't expect they measure the mass in kg, either. But you can multiply by the appropriate factor to convert to whatever units you want; it doesn't change the equation. Edited November 21, 2014 by Strange 1
swansont Posted November 21, 2014 Posted November 21, 2014 On 11/21/2014 at 2:18 PM, DimaMazin said: Do you think scientists measure neutrino KE by Joules? eV is more likely because it's the appropriate scale for atomic/nuclear/particle systems, but ultimately it doesn't matter since the conversion is trivial. 2
DimaMazin Posted November 22, 2014 Posted November 22, 2014 On 11/21/2014 at 2:49 PM, Strange said: I don't expect they measure the mass in kg, either. But you can multiply by the appropriate factor to convert to whatever units you want; it doesn't change the equation. I only have wrongly called energy of rest mass by gravitational energy . Therefore you think I use another equation.
Strange Posted November 22, 2014 Posted November 22, 2014 On 11/22/2014 at 3:45 PM, DimaMazin said: I only have wrongly called energy of rest mass by gravitational energy . Therefore you think I use another equation. No, you were just talking nonsense. Not particularly funny.
DimaMazin Posted November 23, 2014 Posted November 23, 2014 On 11/22/2014 at 4:01 PM, Strange said: No, you were just talking nonsense. Not particularly funny. EK(eV units)=(gamma-1)E0(eV units) * 6.24150934*1018 E0 - rest energy
swansont Posted November 23, 2014 Posted November 23, 2014 On 11/23/2014 at 6:48 AM, DimaMazin said: EK(eV units)=(gamma-1)E0(eV units) * 6.24150934*1018 E0 - rest energy That won't get you energy in Joules, it will get you an answer in eV2/J. However, this doesn't affect the physics of the problem. So what's the point?
DimaMazin Posted November 23, 2014 Posted November 23, 2014 On 11/23/2014 at 10:22 AM, swansont said: That won't get you energy in Joules, it will get you an answer in eV2/J. However, this doesn't affect the physics of the problem. So what's the point? Yes. E=gamma*E0 EK=E-E0 EK(eV units)=gamma*E0(eV units) - E0(eV units)=(gamma-1)E0(eV units)
Strange Posted November 23, 2014 Posted November 23, 2014 On 11/23/2014 at 2:52 PM, DimaMazin said: Yes. E=gamma*E0 EK=E-E0 EK(eV units)=gamma*E0(eV units) - E0(eV units)=(gamma-1)E0(eV units) Is there a point to these rather mangled equations?
swansont Posted November 23, 2014 Posted November 23, 2014 On 11/23/2014 at 2:52 PM, DimaMazin said: Yes. E=gamma*E0 EK=E-E0 EK(eV units)=gamma*E0(eV units) - E0(eV units)=(gamma-1)E0(eV units) What is the point? While unit consistency is important (e.g. everything here has units of energy) the actual unit system used is a secondary consideration — it does not need to be specified in the equation. 1
DimaMazin Posted November 23, 2014 Posted November 23, 2014 On 11/23/2014 at 3:04 PM, Strange said: Is there a point to these rather mangled equations? Let's check. gamma=2 E0=1eV then Etotal=2eV and EK=1eV E0=EK it's correct when gamma=2
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