Jump to content

Extraction of Sodium chloride


Primarygun

Recommended Posts

I thought of a method to prepare sodium chloride solid.

First, pour a certain amount of hydrochloric acid into sodium hydroxide, add a few drops of methyl orange with titration, stop when the colour turns from yellow to red. There are some excess acid mixed with a solution of sodium chloride. Evaporate with steam bath and get the filtrate (crystal), wash it with distilled water and dry it. Is it a good method?

 

Moreover, I want to ask why the change of pH value is very little when an acid is adding to an alkali.

Link to comment
Share on other sites

Sounds pretty good to me you may have some methyl orange contamination but that would be very minor. To answer your question there is a very large PH difference when titrating strong acids with strong bases. The curve would look like a slight increase followed by a very steep increase followed by slight increase. The reason you can use a variety of different indicators for strong acid/base titrations is that the equivalence point value is simlilar the value for a large range of PH values.

Hope that made sense.

 

~Scott

Link to comment
Share on other sites

excess HCL will indeed work, that way all you`ll need is a bit of litmus paper or universal indicator paper and look for mild Red color, the HCL will evaporate off without a problem.

 

that`s the method I`de employ :)

Link to comment
Share on other sites

The first two titration curves refer to strong acid/base titrations Here You can see the rapid PH change, you could use an indicator that changes at 7 8 9 6 5 4 you will get the same result even though the exact equivilance point is at 7. For other titration where the equivilance point dosn't have alot of values similar to it you should use a PH meter to determine the equivilance point. The HCl is not reacting with the methyl orange so adding excess HCl is not going to help with contamination by the methyl orange.

 

~Scott

 

Edit: I would also suggest not using litmus it is one of the harder ones to see the colour change. There are other indicators that are easyer to see the colour change.

Link to comment
Share on other sites

he means skipping the meth orange all together I think.

and litmus will be just fine for the red/pink from the blue paper.

 

or as I mentioned the universal indicator paper that does the whole PH range on a scale, you only need a slight red/pink change :)

Link to comment
Share on other sites

Ok i think i get what your asking...Your saying why is the PH change at the biggining of the titration so slight compared to the PH change around the equivalence point. I think it is to do with the concentrations of the solutions at the start of the titration the concentration changes only slightly as it is neutralised. When it is approching the equivalence point the PH varies quickley due to the the fact the concentration is dropping from a small value to zero very quickley.

 

To answer your other question salt devived from the evap of sea water, there will be a mixture of metal chlorides approximately 98% of the will be sodium chloride while the other 2% will be other metal salts like magnesium, calcium, pottassium...Table salt on the other hand is much more pure about 99.9% with small amounts of potassium iodate. So if your looking for pure NaCl then iodised table salt is a fairly good choice.

 

~Scott

 

Edit: did you check out the link i posted in post No5 ?

Link to comment
Share on other sites

Edit: did you check out the link i posted in post No5 ?

Yes, but I think I am trapped by a small problem which cannot be answered in that web site though it contains lots of information of titration, such as weak-weak, strong ../

Link to comment
Share on other sites

I think that both combination of water molecules fron hydrogen ions and hydroxide ions and the addition of water into the solution speed up the lowering of the pH value.

 

To me this dosen't make sense maybe you could reword it?

 

~Scott

Link to comment
Share on other sites

Ah right interesting point, I think that it would maybe effect the values above and below the equivalance point but not at it because when a solution is neutral it cant be diluted make sense? So when you add 1molL of NaOH to 1molL HCl it dosen't matter how much water is present because the amount of acid it take to neutralise base is the same no matter how much water is present...

 

~Scott

Link to comment
Share on other sites

Yes it does that why i said the small dilution effect would change the PH value up untill the equivalence point when the solution is neutralised. Now that the solution is neutralised you cant diluite a neutral solution so the molarity of any acid or base is zero. That is why the end result is the same regaurdless of the dilution effecting the results prior the the equivalence point.

 

~Scott

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.