kingjewel1 Posted March 16, 2005 Posted March 16, 2005 Hi there guys! this one's interesting but got me stumped. How would i show that the values of x at which sinxe^(-sinx) has stationary points form an arithmetic sequence? Thanks!
bloodhound Posted March 17, 2005 Posted March 17, 2005 i assume you meant [sinx][exp(-sinx)]. just do the most obvious thing which is to find its derivative. which comes out to be [cosx]exp[-sinx] - [sinx][cosx]exp[-sinx]. to find the stationary points , find points such that the derivative at the point is zero. so setting that to 0 we get [cosx]exp[-sinx] - [sinx][cosx]exp[-sinx] = 0 iff cosx - sinx[cosx] = 0 as the exponential is never 0. so we have either cosx = 0 or sinx = 1 which gives just the same arithmetic sequence of solutions namely (pi/2 + n*pi), where n ranges over the integers.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now