Martin Posted March 19, 2005 Share Posted March 19, 2005 ... I've been wondering about the secret of 137 for a long time. What I do already know' date=' is that in the simple Bohr model, the speed of an electron is 137th the speed of light in the CM frame. NIST value for the fine structure constant: [math'] \alpha = 7.297352568 \times 10^{-3} [/math] [math] \frac{1}{\alpha} = 137.0359991 [/math] since you like to calculate (as well as words and mental imagery) and since you know V^2/R we can verify that in the planetary model H atom the speed of electron in its groundstate (lowest angular momentum hbar) is 1/137 this shows again how handy that V^2/R tool is also y'shd know that angular momentum is MVR the ordinary MV momentum times the lever-arm radius which is included because bigger radius gives the regular MV momentum extra leverage Like the electron is this little planet in circular orbit with some V and some R (which by the coolness of nature we dont have to know ahead of time) I AM GOING TO USE UNITS WHERE hbar = c = 1 now the interaction or coupling between the proton and the electron is force x R^2 = 1/137 and the force = M V^2/R (mass x accel) so 1/137 = force x R^2 = R^2 x MV^2/R = MV^2R = MVR x V now if it is the groundstate then it has the smallest amount of angular momentum which is hbar, so MVR = hbar = 1 therefore in the above eqn 1/137 = MVR x V we just drop MVR out and we have V = 1/137 Link to comment Share on other sites More sharing options...
zazzzoom Posted March 20, 2005 Share Posted March 20, 2005 space does not go on forever space ends that way space has a shape and space can move from one shape to another shape Link to comment Share on other sites More sharing options...
Sayonara Posted March 20, 2005 Share Posted March 20, 2005 Errr... okay. Link to comment Share on other sites More sharing options...
Johnny5 Posted March 20, 2005 Share Posted March 20, 2005 since you like to calculate (as well as words and mental imagery) and since you know V^2/Rwe can verify that in the planetary model H atom the speed of electron in its groundstate (lowest angular momentum hbar) is 1/137 this shows again how handy that V^2/R tool is also y'shd know that angular momentum is MVR the ordinary MV momentum times the lever-arm radius which is included because bigger radius gives the regular MV momentum extra leverage Like the electron is this little planet in circular orbit with some V and some R (which by the coolness of nature we dont have to know ahead of time) I AM GOING TO USE UNITS WHERE hbar = c = 1 now the interaction or coupling between the proton and the electron is force x R^2 = 1/137 and the force = M V^2/R (mass x accel) so 1/137 = force x R^2 = R^2 x MV^2/R = MV^2R = MVR x V now if it is the groundstate then it has the smallest amount of angular momentum which is hbar' date=' so MVR = hbar = 1 therefore in the above eqn 1/137 = MVR x V we just drop MVR out and we have V = 1/137[/quote'] This is the kind of thing I've been looking for, I'm going to need time to digest it. Alright man. Link to comment Share on other sites More sharing options...
zazzzoom Posted March 25, 2005 Share Posted March 25, 2005 space does not expand space ends in all directions that way space has a shape Link to comment Share on other sites More sharing options...
swansont Posted March 25, 2005 Share Posted March 25, 2005 space does not expand space ends in all directions that way space has a shape Bald assertions with no discussion of actual data or theory, and in threads where it is not really related. This is getting rather tiresome. Do you have a point, or are you just trying to be annoying? Can you engage in a manner somewhat above first-grade level? What's next, a treatise on rubber vs glue? Link to comment Share on other sites More sharing options...
Ophiolite Posted March 25, 2005 Share Posted March 25, 2005 I believe, swansont, that zazzzoom is trying to establish that the shape of space conforms to the internal shape of his skull. He certainly has me convinced. Link to comment Share on other sites More sharing options...
Spyman Posted March 30, 2005 Share Posted March 30, 2005 I would like to get a grip on the speed of the expansion and acceleration buy doing some simpler calculations myself. If as an example the Sun has a twin star located 10 billion lightyears away, how long would it take for the light from it now to reach Earth in the future ? What values do I need to know and what are the most resent measurements of them with toleranses ? Link to comment Share on other sites More sharing options...
Martin Posted March 31, 2005 Share Posted March 31, 2005 I would like to get a grip on the speed of the expansion and acceleration buy doing some simpler calculations myself. If as an example the Sun has a twin star located 10 billion lightyears away' date=' how long would it take for the light from it now to reach Earth in the future ? What values do I need to know and what are the most resent measurements of them with toleranses ?[/quote'] hello, I just saw this post. it is a very good idea. I wish i had seen it earlier. first I would suggest playing around some with ned wright calculator like, put in redshift z = 5.8 that would be for a star with was located at exactly 4 billion LY from us at the moment when the universe was exactly 1 billion years old and at that moment it emitted light that reached us today there are not simple algebraic formulas for it, the formulas involve integrals, so Ned Wright has put this calculator up for his students and others to use Ned Wright's calculator http://www.astro.ucla.edu/~wright/CosmoCalc.html Link to comment Share on other sites More sharing options...
Spyman Posted March 31, 2005 Share Posted March 31, 2005 there are not simple algebraic formulas for it, the formulas involve integrals, so Ned Wright has put this calculator up for his students and others to useNed Wright's calculator is great, but it calculates when the light was sent out in the past to reach us now and I want to calculate if the light is sent out now when it will reach us in the future.I managed to do that with the calculator by changing the Hubble constant to 2.65 but since the calculator is not ment to be used that way the answere is likely to be wrong, "The light travel time was 300.451 Gyr", it seems very high. Anyhow I would like to try calculating myself, so I can understand why and how, if You or someone have the time to show me how to do it. Link to comment Share on other sites More sharing options...
Martin Posted March 31, 2005 Share Posted March 31, 2005 Ned Wright's calculator is great' date=' but it calculates when the light was sent out in the past to reach us now and I want to calculate if the light is sent out now when it will reach us in the future.I managed to do that with the calculator by changing the Hubble constant to 2.65 but since the calculator is not ment to be used that way the answere is likely to be wrong, "The light travel time was 300.451 Gyr", it seems very high. ....[/quote'] I am glad you liked the calculator. for completness here are links to both Ned Wright's http://www.astro.ucla.edu/~wright/CosmoCalc.html Siobahn Morgan's http://www.earth.uni.edu/~morgan/ajjar/Cosmology/cosmos.html homepage for Siobahn in case you want to see who she is http://www.earth.uni.edu/smm.html homepage for Ned in case you want to see who he is http://www.astro.ucla.edu/~wright/intro.html I believe that these calculators can work to tell light travel times in future years, not only in past years. I will try something with siobahn calculator: this is not quite right but I set Omegamatter = 0.01 and Lambda = 0.99 and H = 60 and for redshift z = 2.4 or 2.5 I got something like what you were talking about. we were looking back, the age of the universe was some 33 billion years, so we were 20 billion years in the future looking back at the present, and at the present time the thing was 9 or 10 billion LY away from us, and the light took 20 billion years to get to us. have to turn in for now, maybe give it another try in the morning. Link to comment Share on other sites More sharing options...
Spyman Posted April 1, 2005 Share Posted April 1, 2005 I got something like what you were talking about.we were looking back' date=' the age of the universe was some 33 billion years, so we were 20 billion years in the future looking back at the present, and at the present time the thing was 9 or 10 billion LY away from us, and the light took 20 billion years to get to us.[/quote']Much smaller value than I got and more likely. But I still would want to make the calculations myself, so I can understand which values I need and what they stands for. To make it easier for myself, I don't need to know the redshift or what speed the star would disperce from us, or which distant it will have in the future. Just how to calculate how long time the light will take to reach us from a chosen distans, if the localy speed is ruled out. I know this would involve the Hubble constant and the speed of light but what more and how ??? Link to comment Share on other sites More sharing options...
revprez Posted April 3, 2005 Share Posted April 3, 2005 vast reaches of space (and the galaxies contained there) are receding from us at speeds greater than c and this does not contradict special relativity. The distance between two distant points may open up at a rate greater than c as measured by some observer at a third point, but this has nothing to do with comparing reference frames. Maybe this misunderstanding about expansion is due to how easy it is to replace "two points apart from mine" with "one distant point and myself." I don't know. Rev Prez Link to comment Share on other sites More sharing options...
Martin Posted April 3, 2005 Share Posted April 3, 2005 hello Spyman and Rev, I have not been checking systematically and missed finding your posts till just now. on my way to bed now but will try to reply tomorrow. Spyman's problem seems hard. need to assume some value for the cosmological constant, also the hubble parameter. let us start with a modest size distance. something today is 1 billion LY distant and today it sends a flash of light in our direction. how long, asks he, before we see the flash. (have to allow for accelerated expansion of space thus which the flash of light will travel) right now too sleepy to even consider it, but even wide awake might have trouble. Rev can you see how to calculate it? Link to comment Share on other sites More sharing options...
Spyman Posted April 5, 2005 Share Posted April 5, 2005 Spyman's problem seems hard. need to assume some value for the cosmological constant, also the hubble parameter.Sounds to hard for my low level of math, maybe I should just give it up ? I thought it could be viewed in a simple way, like to racing cars which starts at different positions with different speeds, the slower one with the head start also accelerates. Time taken for the faster car to reach the slower one with head start. The distant star is viewed as in rest, Earth is the slower car that accelerates with a head start and light is the faster car with constant speed. Time taken for light to reach Earth. Link to comment Share on other sites More sharing options...
Martin Posted April 5, 2005 Share Posted April 5, 2005 spyman, I've been involved with other stuff I think it is not such a hard problem and that a simple approximate formula could be found. Because the universe is considered already 73 percent dark energy (which doesnt thin out as space expands whereas the 27 percent that is matter does thin out) and that 27 percent is getting less all the time as matter thins out, so the 73 percent is getting more all the time (because the dark energy density stays constant so as matter thins out it becomes more important) therefore in the standard ("Lambda CDM") model the future is simple to approximate, just put the dark energy fraction equal 100 percent and the matter fraction 0 percent----which is what it is tending to in the limit. so then no basic parameter is changing and it should be a straightforward calculation. it wont be quite perfect because 73 is not 100, but it will be a reasonable approximation Revprez might very well be able to help, if he checks this thread and has a moment. anyway not to give up just be patient. eventually one of us will see it and it will be simple. (if you try some science question board, like "Ask the Astronomer" and get an answer please post it here) Link to comment Share on other sites More sharing options...
Spyman Posted April 6, 2005 Share Posted April 6, 2005 OK, I will wait and see what happens... BTW Just want to clarify that I wish to understand the calculation also not just having a formula. Link to comment Share on other sites More sharing options...
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