Jump to content

Recommended Posts

Posted (edited)

Has anyone see a Lagrangian of the following type before? If so where?

 

 

Consider [math]\mathbb{R}^{2}[/math] equipped with local coordinates [math](x,y)[/math], then then Lagrangian I am interested in is of the form

 

[math]\mathcal{L} = \dot{x}\dot{y} - y^{2}[/math]

 

where I have set any necessary dimensional constants to 1.

 

I won't say exactly where I have encountered Lagrangians like this quite yet, but I will later once I have finished the work. Right now I was wondering if anyone has seen something similar in any context?

 

Technically it is of mechanical type but not what I would call standard.

Edited by ajb
  • 3 weeks later...
Posted

Yes. I know this. It's used in weapons technology. The code is a bit dubious in it's nature that you speak of though. Thoroughness.

Posted

Yes. I know this. It's used in weapons technology. The code is a bit dubious in it's nature that you speak of though. Thoroughness.

I was not expecting that...

 

Anyway you can show that this Lagrangian is classically equivalent to

 

[math]L' = \frac{1}{2}(\ddot{x})^{2}[/math]

 

and we have a higher order Lagrangian.

 

What at first seems strange to me is that y is like an auxiliary field, but it is dynamical. Up to a numerical factor and a sign y is the acceleration of x. I was wondering if some Lagrangian like that in terms of x and y naturally appears in some applications, maybe not as higher order Lagrangians are not too common and I would say not very well studied.

Posted

The most unusual thing about it is that the equations of motion are third-order. The closest thing I've seen would be a classical self-force, like the Abraham-Lorentz Force (and all the problems associated with it), which could be expressed in a Lagrangian like the following:

 

[math]L= (\dot{x})^2-k(\ddot{x})^2[/math]

Posted

There are a few higher order Lagrangians discussed in the literature, these arise due to simplifications of the model and for sure cannot be fundamental as they break Newton's laws. However, it is not like the literature is full such examples.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.