Cagemine Posted January 22, 2015 Share Posted January 22, 2015 Hi, I am seeking advice, direct or indirect (link to helpful resources), on transforming bending moments from local to global coordinate system using 3-D permutation tensor. For example, I have a series of bending moments acting on a node but in a local coordinate system and I want to transform these to the global coordinate system. From my reading on this the 3-D permutation tensor is used in conjunction with a function for the local bending moments and transforms them into global bending moments at that node. Global coordinate system [1 0 0 ; 0 1 0 ; 0 0 1] Local coordinate system [ 0.707 0.707 0 ; -0.707 0.707 0 ; 0 0 -1] A vector P <px, py, px> represents the beam and is parallel to the global X-axis, P = < 1 0 0 > The following local bending moments are applied (counter clockwise positive) Moment about local x-axis, mx = 0 units Moment about local y-axis, my = 2 units Moment about local z-axis, mz = 0 units What are the resulting global moments. The general formula used is: M1i = εjik [mz1 pk y1j - my1 pk x1j + mx (x1j y2k - y1j x2k)/2] 1 or 2 mean the near or far ends of a beam ijk take the form of 1,2,3 (representing x,y,z) I have determined the answer to be: Moment about global X-axis, Mx = -1.41 units (anti cyclic permutation) Moment about global Y-axis, My = 1.41 units (cyclic permutation) Moment about global Z-axis, Mz = 0 units I have an issue with my understanding of the 3-D permutation tensor. Thus my true question being, How does one determine what the permutation should be, cyclic (123) or anti-cyclic (321) in this Cartesian coordinate axis environment? Regards, Cage Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now