psi20 Posted March 20, 2005 Posted March 20, 2005 I'm trying to prove that, hopefully this comes out right, [math]\sum_{r=0}^{n}{(-1)}^{r}{_n}C{_r}{(n+1)}^n = n![/math] Can anyone help? The pattern is from 1 4 9 3 5 2 1 8 27 64 7 19 37 12 18 6 1 2 1 etc.
uncool Posted March 20, 2005 Posted March 20, 2005 I'm not sure about the sum part, but the others come from taking differences. Here iswhy it works: ((x+1)^n-x^n) = nx^(n-1)+n*(n-1)*x^(n-2)/2 + ... So the coefficient of the first term will be n. You then subtract again, because you eventually want to get a constant number times the first term without the x value. This leaves you with n*(n-1). Then you subtract again, leaving you with n*(n-1)*(n-2) . . . Then you subtract again, leaving you with n*(n-1)*(n-2)*....*3*2*1 = n! All the other coefficients cancel out. Hope this helps. -Uncool-
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