Jump to content

Mathematics


Recommended Posts

Guest RYWIL
Posted

How do I prove that lim x->a [xf(x) ] = cL, given that Lim x->a f(x) = L?

Posted

I assume you mean that lim (x->a) [xf(x) = aL]

If lim(x->a) [f(x) = L]

There is a neighborhood around a where f(x) is continuous

Therefore, there is a neighborhood around a where x f(x) is continuous

In the neighborhood, the function returns x f(x)

Since both approach finite values, the limit of the product is the product of the limits.

Therefore, the limit is aL.

-Uncool-

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.