horsebox Posted April 20, 2015 Share Posted April 20, 2015 (edited) As an example, I'll use the rs33 SNP. For Europeans, A has a frequency of 0.220 and G = 0.780. Then for the genotypes: AA = 0.051, AG=0.339, GG=0.610. I would assume the genotype frequencies are a matter of statistics. Maths isn't my strong point, I can't figure out how to calculate them from the allele frequencies. Also I've seen some weird things on dbsnp like two allele frequencies A=0.50,C=0.50 adding up to AC=1.00 which makes me wonder if its even possible to calculate them with a simple mathematical formula. But if thats the case, how can they determine the allele frequencies if they're not even related to the genotype frequencies? EDIT: I checked out one of those online calculators, and they give the expected results (for AA and GG, the value is what you get when you square the allele frequencies), they don't work on these real life examples. Edited April 20, 2015 by horsebox Link to comment Share on other sites More sharing options...
MonDie Posted April 20, 2015 Share Posted April 20, 2015 (edited) I'm not sure I follow 100%. If [math]p + q = 1[/math] is true but [math]p^2 + 2pq + q^2 = 1[/math] is false, then one of the Hardy-Weinberg assumptions has been violated. ideal - - actual 0.0484 - - 0.051 0.3432 - - 0.339 0.6084 - - 0.610 They're approximately the same. I wouldn't expect them to ever be exact. Population size is always finite, thus so are number of mate pairings and number of deaths/selections, leaving some room for chance deviation. Edited April 20, 2015 by MonDie Link to comment Share on other sites More sharing options...
Roamer Posted April 21, 2015 Share Posted April 21, 2015 You gotta multiply the frequencies. The frequencies are basically percentages(0.780=78%) So to calculate AG you multiply 0.78 by 0.22 and get something around 0.18. Note that numbers become smaller after multiplication because you multiply numbers which are smaller then one. Link to comment Share on other sites More sharing options...
MonDie Posted April 21, 2015 Share Posted April 21, 2015 (edited) What an embarrassing mistake! If [math]p + q = 1[/math] is true but [math]p^2 + 2pq + q^2 = 1[/math] is false, then one of the Hardy-Weinberg assumptions has been violated. I meant: If [math]p^2, 2pq,[/math] and [math]q^2[/math] do not reflect the observed genotype frequencies! You gotta multiply the frequencies. The frequencies are basically percentages(0.780=78%) So to calculate AG you multiply 0.78 by 0.22 and get something around 0.18. Note that numbers become smaller after multiplication because you multiply numbers which are smaller then one. Multiply by two for the heterozygous genotype! Edited April 21, 2015 by MonDie Link to comment Share on other sites More sharing options...
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