Prometheus Posted May 10, 2015 Posted May 10, 2015 So I want to find the Laplace transform of: [latex] f(t)=\alpha e^{-\alpha t} + \beta e^{-\beta t}[/latex] I make it: [latex]f^*(s)=\frac{\alpha}{\alpha+s}+\frac{\beta}{\beta+s}[/latex] Which I thought simply follows from the linearity of the integral operator. But according to my lecture notes it is: [latex] f^*(s)=(\frac{\alpha}{\alpha+s})(\frac{\beta}{\beta+s}) [/latex] I'm hoping there is a mistake in the lecture notes, otherwise I've totally misunderstood things. I would appreciate it if anyone could comment on which answer is correct.
imatfaal Posted May 10, 2015 Posted May 10, 2015 http://www.wolframalpha.com/input/?i=laplace+transform+f%28t%29%3Dxe^{-yt}+%2B+ye^{-yt} 1
Prometheus Posted May 10, 2015 Author Posted May 10, 2015 Cheers. Good old wolfram alpha, didn't even occur to me to check there.
Prometheus Posted May 19, 2015 Author Posted May 19, 2015 Turns out it was the product, not the sum. What I neglected to add was that I was dealing with random variables. I knew this was true for Gaussian random variables, but didn't know it extends to all random variables (which what it seems to be true, i'll have to find out exactly why, but I know it's related to convolution theorem).
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