razorfane Posted March 29, 2005 Posted March 29, 2005 It is 1:00 on a grandfather clock(a non-digital one), what time will it be when the minute hand and the hour hand form a 90 degree angle for the first time?
Dapthar Posted March 29, 2005 Posted March 29, 2005 It is 1:00 on a grandfather clock(a non-digital one), what time will it be when the minute hand and the hour hand form a 90 degree angle for the first[/b'] time? 1:21:49.0909... (Time is in hours:minutes:seconds) Of course, this assumes continuous movement of the minute and hour hands.
apuldube Posted April 11, 2005 Posted April 11, 2005 can you help me as to how did you calculate that
Algebracus Posted April 11, 2005 Posted April 11, 2005 Let us say that this happens x seconds after 1 o'clock. Then the minute hand has moved (x seconds)/(3600 seconds in an hour)*(360 degrees per hour) = x/10 degrees, and the hour hand has moved (x seconds)/(3600 seconds in an hour)*(30 degrees per hour) = x/120 degrees. We have x/10 = x/120 + 120 (90 + 30, since we started at 1 o'clock) (+360k, k an integer,but in this case k = 0, since we are interested in the first case) and therefore, 11x/120 = 120, or x = 120*120/11 = 1309 + 1/11. Now, 1309 = 60*21 + 49, so it has passed 21 minutes and 49,090909... seconds.
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