Thorham Posted June 27, 2015 Posted June 27, 2015 In this integral (error function), what is d and what is t? This stuff is hard to find for math noobs 1
ajb Posted June 27, 2015 Posted June 27, 2015 t looks to be a real number. dt is a formal symbol that tells you what you are integrating with respect to. For simple integrals like that there is no more in it really. You can use Riemann's definition. 1
Unity+ Posted June 27, 2015 Posted June 27, 2015 (edited) In this integral (error function), what is d and what is t? This stuff is hard to find for math noobs What do you mean what is d and what is t? That is part of integral notation. EDIT: I thumbed up the wrong post. I meant just to thumb up ajb. Oops? Edited June 27, 2015 by Unity+ 1
Thorham Posted June 27, 2015 Author Posted June 27, 2015 (edited) t looks to be a real number. dt is a formal symbol that tells you what you are integrating with respect to. For simple integrals like that there is no more in it really. You can use Riemann's definition. I have no Idea what that means. Could someone explain this as if I'm a four year old? Edited June 27, 2015 by Thorham
Unity+ Posted June 27, 2015 Posted June 27, 2015 (edited) I have no Idea what that means. Could someone explain this as if I'm a four year old? It means that you are taking the reverse derivative of an equation with respect to a particular variable. For example, let's say you have ax+b and the point is to integrat this equation with respect to x, or apply the integral to that particular variable. You would treat every other variable like a constant and simply integrate x. ax^2/2 + bx Edited June 27, 2015 by Unity+
Thorham Posted June 27, 2015 Author Posted June 27, 2015 It means that you are taking the reverse derivative of an equation with respect to a particular variable. For example, let's say you have ax+b and the point is to integrat this equation with respect to x, or apply the integral to that particular variable. You would treat every other variable like a constant and simply integrate x. ax^2/2 + bx I don't understand that, either. The gaps in my maths knowledge are just to large. Perhaps it's time to go and do something about that.
Unity+ Posted June 27, 2015 Posted June 27, 2015 I don't understand that, either. The gaps in my maths knowledge are just to large. Perhaps it's time to go and do something about that. What about it do you not understand?
Thorham Posted June 27, 2015 Author Posted June 27, 2015 What about it do you not understand? Everything. I took a quick look at integrals and thought it wasn't so hard, but I don't get any of it. I should probably just take my time to learn integrals properly.
mathematic Posted June 28, 2015 Posted June 28, 2015 Everything. I took a quick look at integrals and thought it wasn't so hard, but I don't get any of it. I should probably just take my time to learn integrals properly. Good idea!!!!! You need to understand the basic notation. 1
Unity+ Posted June 28, 2015 Posted June 28, 2015 Everything. I took a quick look at integrals and thought it wasn't so hard, but I don't get any of it. I should probably just take my time to learn integrals properly. Before learning integrals, I think you should start with derivatives first. If that is confusing, I would start with limits of functions then.
LaurieAG Posted June 28, 2015 Posted June 28, 2015 Everything. I took a quick look at integrals and thought it wasn't so hard, but I don't get any of it. I should probably just take my time to learn integrals properly. The integral is just the opposite of the derivative so the tutorials on this forum should give you a helping hand. http://www.scienceforums.net/topic/29473-introduction-to-calculus-differentiation/ http://www.scienceforums.net/topic/4108-calculus-i-lesson-1-a-background-to-differentation/ http://www.scienceforums.net/topic/4182-calculus-i-lesson-2-a-continuation-from-first-principles/ 1
ajb Posted June 28, 2015 Posted June 28, 2015 Or you you can think in terms of the area under the graph. If you ploy y = f(x) then the integral over x1 to x2 is the area under the graph between these two points. 1
Strange Posted June 28, 2015 Posted June 28, 2015 Everything. I took a quick look at integrals and thought it wasn't so hard, but I don't get any of it. I should probably just take my time to learn integrals properly. This is a good intro to calculus: https://www.coursera.org/learn/calculus1
Thorham Posted June 29, 2015 Author Posted June 29, 2015 The integral is just the opposite of the derivative so the tutorials on this forum should give you a helping hand. http://www.scienceforums.net/topic/29473-introduction-to-calculus-differentiation/ http://www.scienceforums.net/topic/4108-calculus-i-lesson-1-a-background-to-differentation/ http://www.scienceforums.net/topic/4182-calculus-i-lesson-2-a-continuation-from-first-principles/ This is a good intro to calculus: https://www.coursera.org/learn/calculus1 Thanks for those links
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