Im finally doing some calculus @ college...

[Adrian]

and its EASY! im teaching myself from the book because the prof. sucks!

 

i like this better than other types of math...i dont know why...

 

ill probably be posting in here a lot throught the semester

 

 

EDIT: by semester i mean 4 weeks...summer classes compress 16 weeks to 4

[mike]

Ha, I just took a 3 week Calc class... 4 days a week, 4 hours a day...

 

It was actually.....fun... I understood it, and was able to do what was presented to me...

[kenel]

I like calculators too, especially the ones with the games.

[PlanetCpp]

i cant imagine ANYONE likeing calc 2, i hated calc 1 but ill take it anyday over this ;o(

maybe calc 2 wouldnt be so bad in a whole semster, im taking it in the summer. if your good with trig, and i mean really good then you might actually like calc 2, but you have to remember things like

sin²x+cosx/tan2x+tan²x can be substituted by:

1=cosx-2sin²x(tanxsecx)-(sin^(-1)x)

thats wrong (fake) or whatever but you get the drift

3 more classes to go calc 3, linear algebra, and probability

oh god i cant wait!!!

im gonna erase every bit of math knowledge from my brain once i walk out of the probability final:D

[mike]

eh i put all those 1=cosx-2sin²x(tanxsecx)-(sin^(-1)x)

lines in my calculator ;P

[Epsilon]

haha, memorize your basic trig identities!

 

i knew a guy who had tables of them in his ti-89, needless to say, his exams were easy heh

 

but i think it helps to memorize your basic identites, like:

 

tan(x) = sin(x)/cos(x)

sin^2(x) + cos^2(x) = 1

sin(x) = cos(pi/2 - x) (same with any trig function and its cofunction)

sin(a +- b), cos(a +-b)

and some others i didn't list...

 

and use what you know to derive something else, e.g. using sin(a +- b)/cos(a +-b) = tan(a +- b) to derive an identity for the sum/difference tangent formula...

 

at least, this helped me out.

 

if i knew d/dx sin(x) = cos(x), then i can find out d/dx cos(x) by using the fact that cos(x) = sin(pi/2 - x), therefore i find d/dx sin(pi/2 - x) which is cos(pi/2-x) * (-1), and since cos(pi/2-x) = sin(x), we have d/dx cos(x) = -sin(x)

 

i can go on but you get the idea

[mike]

:puts everything in his calculator: