annlee Posted September 13, 2015 Posted September 13, 2015 (edited) hi there I am new! I am doing an experiment to obtain pure liquid from smoke gas from: steam boiler vs car exhaust without gass loss, then will send to a lab to analyze its CO2 and other parameters, questions: - is this liquefaction experiment possible? (do I need to cool-up smoke before and how? is this smoke liquified-able...) - which industrial device(s) to use? (cheap and small if possible, consider must absorb smoke continuously...) Thanks in advance Edited September 13, 2015 by annlee
John Cuthber Posted September 13, 2015 Posted September 13, 2015 What are you trying to do? If you have a pure liquid there is no point in analysing it.
fiveworlds Posted September 13, 2015 Posted September 13, 2015 The short answer is yes it is possible using fractional distillation.
Endy0816 Posted September 13, 2015 Posted September 13, 2015 Should probably look into gas analysis instead. You can convert a gas into a liquid via typically cooling and pressurization, but could easily get expensive depending on the gasses involved. What you'll want to do is look at the phase diagrams for the gasses you expect to see and work from there to figure out feasibility.
annlee Posted September 13, 2015 Author Posted September 13, 2015 (edited) The short answer is yes it is possible using fractional distillation. Should probably look into gas analysis instead. You can convert a gas into a liquid via typically cooling and pressurization, but could easily get expensive depending on the gasses involved. What you'll want to do is look at the phase diagrams for the gasses you expect to see and work from there to figure out feasibility. Thanks guys, this is what I plan to do: - 1st device makes condensation of pollutant air cooling up to 1ºC aprox, so H2O is liquified and this is expulsed out of the system (not needed for analysis) (consider aprox. 1,5grs of air is present per 1gr of gasoline after combustion) - 2nd device takes the resulting gas without water and cool it up to -80ºC (point for CO2) and this liquid is stored the rest of gases are expulsed since this study will consider only CO2 (for now) There are many aspects to point out: pumps, filters, other gases affected by this, devices, continuously air issues, pressure... but, briefly, does it make sense guys? thanks in advance Edited September 13, 2015 by annlee 1
annlee Posted September 14, 2015 Author Posted September 14, 2015 (edited) there is another issue, the storage in liquid state, I may need a sensor into the very high pressure tank to cool it up to keep it liquid: Edited September 14, 2015 by annlee
John Cuthber Posted September 14, 2015 Posted September 14, 2015 There's a few bigger problems. If you cool wet smoky air to about 1C most, but not all, of the water will condense. That water will dissolve some components of the mixture- notably CO2. Also, if you cool air to -80 C none of the CO2 will condense- the temperature of dry ice- about -80C is the temperature where solid CO2 is in equilibrium with the gas at a pressure of 1 atmosphere. But in ordinary air the partial pressure of CO2 is only about a three thousandth of an atmosphere. Gas sampling is difficult (I spent about 20 years working mainly in that field). What are you actually trying to find out.
annlee Posted September 15, 2015 Author Posted September 15, 2015 There's a few bigger problems. If you cool wet smoky air to about 1C most, but not all, of the water will condense. That water will dissolve some components of the mixture- notably CO2. Also, if you cool air to -80 C none of the CO2 will condense- the temperature of dry ice- about -80C is the temperature where solid CO2 is in equilibrium with the gas at a pressure of 1 atmosphere. But in ordinary air the partial pressure of CO2 is only about a three thousandth of an atmosphere. Gas sampling is difficult (I spent about 20 years working mainly in that field). What are you actually trying to find out. Dear John, (for now) I need to find a method to separate CO2 from pollutant air, I have found many expensive, advanced and (ofc patented!) ways: membranes, materials, laser, CaO... not feasible Having a tank at 5ºC and 40 bar to keep CO2 could be feasible but I think it may need a lot of energy, if this energy is stop then the tank may expode since CO2 is turn into gas again In other words, what I need is a cheap and feasible method (not patented) for taking CO2 from pollutant air
fiveworlds Posted September 15, 2015 Posted September 15, 2015 There's a few bigger problems. Including explosions. Also rapid drops in pressure can and will crush things due to atmospheric pressure acting on the object.
John Cuthber Posted September 15, 2015 Posted September 15, 2015 Dear John, (for now) I need to find a method to separate CO2 from pollutant air, I have found many expensive, advanced and (ofc patented!) ways: membranes, materials, laser, CaO... not feasible Having a tank at 5ºC and 40 bar to keep CO2 could be feasible but I think it may need a lot of energy, if this energy is stop then the tank may expode since CO2 is turn into gas again In other words, what I need is a cheap and feasible method (not patented) for taking CO2 from pollutant air Soda lime is fairly cheap and is so old it can't be patented these days. But the real question I'd still like you to answer is why bother?
annlee Posted September 16, 2015 Author Posted September 16, 2015 Soda lime is fairly cheap and is so old it can't be patented these days. But the real question I'd still like you to answer is why bother? very interesting John, now I have something to research I want to absorb the CO2 of steam boiler for 48 hours, which rate % of absortion do you expect? and how much kgs of soda lime will be needed? how to recycle soda lime? btw why do you like signatures THAT much? thanks
imatfaal Posted September 16, 2015 Posted September 16, 2015 ... btw why do you like signatures THAT much? thanks ! Moderator Note The green and red arrows are the forum's reputation system which we encourage members to use. John, like many other staff members, is just highlighting the existence of the reputation system. Each green positive up-rep increases the figure at the end of the post and the member's personal reputation, each red negative down-rep does the opposite. The hope/plan is that if enough people do this then members can quickly tell which advice/answer is well-regarded by the members of the forum. If you hold your mouse over John Cuthber's member name at the top left hand side of a post a little floating box will open - the number in green is the number of times that members have positively recommended one of his posts - ie at least 2441 times. You will note that one of your own posts has been up-voted - probably for asking a sensible question and then following it up with a reasoned response (amazing how rarely this happens); you will also notice that you should now have a positive reputation. There are numerous threads about the reputation system in the Support forum. If you have any more questions - or if anyone else wish to comment that's the arena for further discussion. Thanks
John Cuthber Posted September 16, 2015 Posted September 16, 2015 It's impossible to answer the question about a boiler without knowing what the size, efficency and fuel are but I guess you know how much fuel it uses. Soda lime will take up about a third of its weight of CO2. And if you burn a fuel the carbon in that fuel is converted almost entirely to CO2. So, if we imagine that you burn pure carbon, each atom of carbon will be converted to a molecule of CO2. And the (relative) weight sof those are about 12 and 44 So a given weight of carbon will give 44/12 times that weight of CO2. And it will take about 3 * 44 /12 = 11 times as much weight of soda lime to absorb all that CO2- though I'd suggest using about twice than much to make sure that there is still plenty of soad lime left to absorb the last of the gas at the end of the 48 hours. You could redo this calculation for coal (with a known carbon content) or oil but it won't make much difference. The soda lime would weigh about 20 times as much as the fuel. Obviously, that's not practical on a large scale. They do this sort of thing instead. https://en.wikipedia.org/wiki/Amine_gas_treating As a side point, I could have told you about that earlier if you had said that you were looking at capturing the gas from a steam boiler- rather than gas sampling for analysis. When someone asks you why you want to do something it is often because the best way to do it depends on why you are doing it. So, I will ask you again. Why are you doing this?
annlee Posted September 17, 2015 Author Posted September 17, 2015 (edited) It's impossible to answer the question about a boiler without knowing what the size, efficency and fuel are but I guess you know how much fuel it uses. Soda lime will take up about a third of its weight of CO2. And if you burn a fuel the carbon in that fuel is converted almost entirely to CO2. So, if we imagine that you burn pure carbon, each atom of carbon will be converted to a molecule of CO2. And the (relative) weight sof those are about 12 and 44 So a given weight of carbon will give 44/12 times that weight of CO2. And it will take about 3 * 44 /12 = 11 times as much weight of soda lime to absorb all that CO2- though I'd suggest using about twice than much to make sure that there is still plenty of soad lime left to absorb the last of the gas at the end of the 48 hours. You could redo this calculation for coal (with a known carbon content) or oil but it won't make much difference. The soda lime would weigh about 20 times as much as the fuel. Obviously, that's not practical on a large scale. They do this sort of thing instead. https://en.wikipedia.org/wiki/Amine_gas_treating As a side point, I could have told you about that earlier if you had said that you were looking at capturing the gas from a steam boiler- rather than gas sampling for analysis. When someone asks you why you want to do something it is often because the best way to do it depends on why you are doing it. So, I will ask you again. Why are you doing this? thanks a lot! the amine stuff seems too complex and expensive for this home experiment seems if you have (let's say) smoke with 15% of CO2 from a boiler of 70kgs of combustible (10,5 kgs of CO2 in total), being expulsed in 24 hours, (this is 0,4375kg/hour = 7,3grs/minute), then I may need at least 3 times that weight on soda lime (31,5 kgs) to absorb it, isn't it too bad rate of absortion? regarding soda lime recycling, do you think it would be the same process than for glasses but considering it has CO2 should differ I guess why are you doing this? I am doing a small research to find "feasible methods for separating CO2", this is a topic I have been assigned in my class Edited September 17, 2015 by annlee
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