purplemonkey123 Posted September 30, 2015 Posted September 30, 2015 If 1.20 grams of salicylic acid is reacted with excess methanol, what mass of ester should you expect to achieve theoretically? Molar masses of.. salicylic acid is 138.13g/mol methanol is 32.05g/mol ester (methyl salicylate) is 152.16g/mol Mole ratio 1:1 My work: 1. 1.20 g salicylic acid (1 mol salicylic acid/138.13 g salicylic acid) = 0.008687468 mol salicylic acid2. 0.008687468 mol salicylic acid (1 mol ester/1 mol salicylic acid) = 0.008687468 mol ester3. 0.008687468 mol ester (152.16 g ester/1 mol ester) = 1.32 g ester so 1.32g of ester would be expected. Is my work correct? or do I have to use the excess reagent to find the mass of the product?
hypervalent_iodine Posted October 1, 2015 Posted October 1, 2015 No, you always use the limiting reagent. By definition, it is the component that limits the amount of product formed. Using your molar masses and mass amounts, I get the same answer. 1
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now