Ice-cream Posted April 9, 2005 Posted April 9, 2005 hey can any1 confirm my answer? A hydrogen atom in its ground state absorbs a proton of wavelength 121.5nm. To which higher energy state will it be excited? (a) n=2 (b) n=3 © n=4 (d) n=5 (the answer i got was n = 1.15 so roughly n= 1, using bohr's equation and E = hc/wavelength. but that doesn't match any of the multiple choice answers on the worksheet. wat do u guys think?)
mezarashi Posted April 9, 2005 Posted April 9, 2005 This depends on what level the electron was on. The lowest level it can be in is n=1, so if it has enough energy to jump 1 level, then obviously the answer is (a) n = 2. 1+1 = 2. My own calculations show that the photon gave 10.216 eV of energy to the electron, thus allowing it to jump from n=1 to n=2. n=1 (-13.6eV), n= 2 (-3.4eV) a difference of 10.2 eV. Note that at 0eV, the electron is free from the nucleus (conduction band).
Dave Posted April 9, 2005 Posted April 9, 2005 The question says that the electon is in its ground state.
swansont Posted April 9, 2005 Posted April 9, 2005 I agree with Mez. 10.2 eV, which is the jump to the n=2 state.
Ice-cream Posted April 9, 2005 Author Posted April 9, 2005 thanx guys, i realised wat i did wrong (i used n=0 for ground state lolz)
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