frankenstein18 Posted November 24, 2015 Posted November 24, 2015 Can someone tell me if I'm on the right track with these intramolecular reactions? For a) I think that an epoxide is formed after NaH takes a Hydrogen from the OH substituent and then the electrons travel making the Cl leave. Then for b I know an epoxide can't form since the OH and the Cl are on the same side. I think the NaH would take the H, so would the product be a resonance structure??? For c. I think it's a 5 carbon hetero-cyclic ring with an Oxygen closing the ring + NaH2 and Br- And for d. I think another hetero cyclic ring happens but I don't know what it would look like.I don't know it's substituents or how long it would be since it's not a long chain like how c was. Am I in the right direction?
BabcockHall Posted November 24, 2015 Posted November 24, 2015 I think that when sodium hydride accepts a proton, the side products will be Na+,Br- and H2 gas. I see no reason why an epoxide could not form in d.
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