C2H5OH Posted December 11, 2015 Posted December 11, 2015 Hello everybody I have a problem with one exercise. Dimedon shall react with NaOH and an excess of Br2. What is the product of the reaction? I thought about deprotonating the Dimedon between the two Keto-groups and form the enolat. But does the Br2 is added then or does something else happens first? Thanks for your help
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