toki Posted December 30, 2015 Posted December 30, 2015 A simple pendulum sinks in water. The density of water is 1000kgm-3. The density of the bob is 1500kgm-3. The effective length of the pendulum is 1m. Gravitational acceleration is 9.8ms-2. What is the period of the pendulum? Neglect viscosity. i can measure the period in the air or free place.but how can i measure the friction of water?
Klaynos Posted December 30, 2015 Posted December 30, 2015 It says neglect viscosity. What other effect does submerging an object have? 2
studiot Posted December 30, 2015 Posted December 30, 2015 (edited) It says neglect viscosity. What other effect does submerging an object have? +1 toki upward buoyant force Which affects what parameter in the formula for the period of a pendulum? Edited December 30, 2015 by studiot
toki Posted December 30, 2015 Author Posted December 30, 2015 +1 Which affects what parameter in the formula for the period of a pendulum? in the formula T=2pi*root of L/g there is nothing to effect it with out L and g but as far as i know pendulam works in free place.but there is water here but you are right that the upward byuiant force affects the g.because if the bob gets a force F=mg in free place ,in water it will get a force F-f(upward force)
studiot Posted December 30, 2015 Posted December 30, 2015 Firstly a small correction pendulam The word is spelled pendulum Yes you are right the period of the pendulum is equal to 2pi root (l/g). Note the brackets I have added to make the formula clear and correct. However the acceleration term is not g when there are additional forces involved. Remember acceleration = net force / mass The mass has not changed but the net force has changed due to the additional bouyancy force which acts to reduce the gravitational force (weight) and therefore the acceleration. So the pendulum swings mores slowly under water. Here is a record of a practical experiment and explanation. http://www.millersville.edu/physics/experiments/038/index.php 1
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