Rakdos Posted April 12, 2005 Posted April 12, 2005 In this circle how do you find x [math]9^2+(x-3)^2=(x-3)^2[/math] right??
Dave Posted April 12, 2005 Posted April 12, 2005 You can form a pair of simultaneous equations: [math]x^2 + 9^2 = r^2[/math] where r is the radius of the circle, and: [math]x = r-3[/math] Substitute the second into the first and you're done.
Rakdos Posted April 13, 2005 Author Posted April 13, 2005 thanks dave it was a bonus question on a test today and i wanted to know if my anwser was right, it wasn't
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