Mike Smith Cosmos Posted January 21, 2016 Share Posted January 21, 2016 (edited) . This picture of a planet like disc , Appeared on BBC . TV . Last night 20/01/16 Suggestions of an object 10 times heavier than Earth, a gas giant , identified by an American University, Californian Institute of Technology , on the fringes of , yet within , the Solar system Mike Edited January 21, 2016 by Mike Smith Cosmos 1 Link to comment Share on other sites More sharing options...
Strange Posted January 21, 2016 Share Posted January 21, 2016 Note that this hypothetical body has not been observed directly yet. It is based on its effects on other objects in the Kuiper belt: The researchers, Konstantin Batygin and Mike Brown, discovered the planet's existence through mathematical modeling and computer simulations but have not yet observed the object directly. https://www.caltech.edu/news/caltech-researchers-find-evidence-real-ninth-planet-49523 2 Link to comment Share on other sites More sharing options...
sallyjohn85 Posted January 21, 2016 Share Posted January 21, 2016 Orbital duration 20,000 years, Good to know about this news... Link to comment Share on other sites More sharing options...
DrmDoc Posted January 21, 2016 Share Posted January 21, 2016 (edited) Here's a link to a Washington Post article which contains another link to the published paper on the discovery. Edited January 21, 2016 by DrmDoc 2 Link to comment Share on other sites More sharing options...
Willie71 Posted January 21, 2016 Share Posted January 21, 2016 Video: Link to comment Share on other sites More sharing options...
Sensei Posted January 21, 2016 Share Posted January 21, 2016 (edited) I made comparison sheet between Earth, Ice-only planet, same as Earth density and Iron-only planet for object that is 10x more massive than Earth: Radius/volume of planet is calculated from mass/density. Somebody wants to make equation how big will be such object on photo taken from Earth.. ? Edited January 21, 2016 by Sensei Link to comment Share on other sites More sharing options...
Janus Posted January 21, 2016 Share Posted January 21, 2016 I made comparison sheet between Earth, Ice-only planet, same as Earth density and Iron-only planet for object that is 10x more massive than Earth: Comparison.png Radius/volume of planet is calculated from mass/density. Somebody wants to make equation how big will be such object on photo taken from Earth.. ? At its average distance from the Sun (given as 20 times that of Neptune and using the largest radius given (for ice), it would have an angular size of somewhere in the neighborhood of 0.1 arc second, which twice the angular resolution for the Hubble. In other words just resolvable. However, at that distance, it will also get 1/400 as much light as Neptune(per square meter) or 1/363,000 as much as the Earth. Which means it would be lit by about as much light as reaches the ground under a full moon. It is not going to reflect a lot of light back to us, and depending on its albedo, It could take a long exposure time to get any image at all of it. Link to comment Share on other sites More sharing options...
Sensei Posted January 21, 2016 Share Posted January 21, 2016 (edited) At its average distance from the Sun (given as 20 times that of Neptune and using the largest radius given (for ice), it would have an angular size of somewhere in the neighborhood of 0.1 arc second, which twice the angular resolution for the Hubble. In other words just resolvable. Hmm.. I was thinking about something more accurate, like my sheet. Date of year when there is taken photo also matter: in f.e. January Earth is closer to some objects by 300 mln km, while half-year later in June/July it's 300 mln km farther (than in previous closer case). Anyway, thank you. However, at that distance, it will also get 1/400 as much light as Neptune(per square meter) or 1/363,000 as much as the Earth. Which means it would be lit by about as much light as reaches the ground under a full moon. It is not going to reflect a lot of light back to us, and depending on its albedo, It could take a long exposure time to get any image at all of it. If there will done periodical examination of position of planet-to-be, and known stars behind it, planet should hide them, and known star should disappear from photos. We don't need to rely on light reflected/emitted by body, but also by hiding what is behind. Of course, if there is something. Edited January 21, 2016 by Sensei Link to comment Share on other sites More sharing options...
Janus Posted January 21, 2016 Share Posted January 21, 2016 (edited) Hmm.. I was thinking about something more accurate, like my sheet. Without more accuracy in initial data, you aren't going to get more accuracy. Its been said to be an average of 20 times further than Neptune, which gives it a period of ~14,000 yrs, or having a period between 10,000 and 20,000 yrs. So unless you can point to some figures more nailed down than that, a close estimate is all you are going to get. Date of year when there is taken photo also matter: in f.e. January Earth is closer to some objects by 300 mln km, while half-year later in June/July it's 300 mln km farther.Insignificant, really. At the 20 times Neptune distance it is some 600 times further from the Sun than the Earth. So it would be like noted the apparent difference in size between a grain of sand 300 miles away vs one 301 miles away. The major difference will be due to the planet's own eccentricity of orbit, and to work that out you would need all the orbital parameters for it. Anyway, thank you. If there will done periodical examination of position of planet-to-be, and known stars behind it, planet should hide them, and known star should disappear from photos. We don't need to rely on light reflected/emitted by body, but also by hiding what is behind. Of course, if there is something. If you are waiting on an object with that small an angular size to occult a star, you are going likely be in for a long wait. Much better to pin down the expected position of the planet. Do a long enough exposure to detect it, then do the same thing 6 months later and look for a parallax. Edited January 22, 2016 by Janus 3 Link to comment Share on other sites More sharing options...
Robittybob1 Posted January 22, 2016 Share Posted January 22, 2016 Could it just be another gathering of icy objects like another Kuiper Belt and not a planet as such? Link to comment Share on other sites More sharing options...
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