Niha afzal Posted March 21, 2016 Share Posted March 21, 2016 I tried solving this question A gets canceled out bcz the ion Ch2CO2CH3 is not present D gets canceled out bcz its a tertiary compound Camt figure out is it b or c Link to comment Share on other sites More sharing options...
Elite Engineer Posted March 22, 2016 Share Posted March 22, 2016 (edited) The answer is "C", because the electrons on the carbon of the attacking base are directly adjacent to the carboxyl group, permitting this base exist due to stability via the carboxyl group. In short, the strong base in C is the only base that would actually exist, permitting the specific product. ~EE Edited March 22, 2016 by Elite Engineer Link to comment Share on other sites More sharing options...
Niha afzal Posted March 22, 2016 Author Share Posted March 22, 2016 Oooooooh I seee Thanku soo.much:') Link to comment Share on other sites More sharing options...
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