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Posted

I tried solving this question

A gets canceled out bcz the ion Ch2CO2CH3 is not present

D gets canceled out bcz its a tertiary compound

Camt figure out is it b or c

post-116483-0-93465900-1458590949_thumb.jpg

Posted (edited)

The answer is "C", because the electrons on the carbon of the attacking base are directly adjacent to the carboxyl group, permitting this base exist due to stability via the carboxyl group. In short, the strong base in C is the only base that would actually exist, permitting the specific product.

 

~EE

Edited by Elite Engineer

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