Jump to content

Recommended Posts

Posted

Hey guys im back with straight pictures this time .... so happpy :D :D .... anyways this question I tried the same old Q=IT... but this seems like a trick question.

The question at the bottom of the page

post-116483-0-05651700-1459055967_thumb.png

Posted

Since I'm sure you haven't covered differential equations here is another way.

 

Have you done motion under constant acceleration yet?

Posted (edited)

Look at the following correspondences.

 

When all the rates of change are uniform.

 

velocity is rate of change of distance : current is rate of change of charge

So distance ( symbol s) corresponds to charge (symbol q)

 

acceleration is rate of change of velocity : I will call rate of change of current p

 

The kinematics equation

 

s = ut + 0.5 (f t2) Where s is distance, u is initial velocity, t is time and f i acceleration.

 

This equation also applies to your uniform change of current.

 

i = initial current = 100mA

 

the current changes from 100mA to 20 mA in 8 seconds ie (20 - 100) /8 = -10 mA per second.

So p = 10 mA/s2

 

Changing our formula from

 

s = ut + 0.5 (f t2)

 

to

 

q = it + 0.5 (pt2) = 8

 

q = 100 * 8 + (-10 *64) millicoulombs

 

which I think you will find is answer A

 

Edit

 

q = 100 * 8 + 0.5(-10 *64) millicoulombs

 

which I think you will find is answer C

Edited by studiot
Posted (edited)

Good to see you checked my arithmetic, and found the missing 0.5.

 

Students should always do this.

 

:)

 

Incidentally what are you studying

Physics or Engineering Science?

 

I chose this method because I don't know if you have any calculus, which would be the standard method.

Edited by studiot
Posted

I did basic calculus .... im still doing my alevels ...therefore I have both physics and maths .. but basic math

This kinematics working was amazing.. who knew we could relate kinematics and elctricity like this.... this was amazing seriously yet im scared how will I figure out stuff like this. My best bet is practising a loooot! I find no words to thank you :')

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.