Prove It

[Sriman Dutta]

Prove this-

0/0=2

[Function]

This thread frustrates me more than a thread is supposed to for various reasons.

[Daedalus]

Well, technically division by zero is indeterminate and its behavior depends on the function. Considering this, we can easily show that

 

[math]\lim_{x\rightarrow 0} \frac{2x}{x}=2[/math]

[Sriman Dutta]

Right...

Well, there can be another method-

0/0=1^2-1^2/1-1=(1+1)(1-1)/1-1=2

[Endy0816]

0/0 = 1^2-1^2/1-1 = (1+1)(1-1)/1-1 = (1+1) * (1-1)/(1-1) = 2(0/0) = ?

[Function]

Right...

Well, there can be another method-

0/0=1^2-1^2/1-1=(1+1)(1-1)/1-1=2

 

There is so much so wrong with this.

 

For the record: 1² - 1²/1 - 1 = -1

So you say 0/0 = -1

Which is very obviously false and since you have not proven this in a lemma before, it is incorrect to use this in your proof.

 

You seem to have a little problem using parentheses.

You also state that (1+1)(1-1)/1-1 = 2

 

Let's continue with what it says: (1+1)(1-1)/1 - 1 = 2

2 * 0/1 - 1 = 2

-1 = 2

Obviously false.

 

Let's continue with what I think you mean:

(1+1)(1-1)/(1-1) = 2

(1+1)(0)/(0) = 2

2 * 0/0 = 2

Which you cannot use since you try to prove that 0/0 = 2, and now it states that 2 * 0/0 = 2. Such thing can never be true. As stated before, 0/0 is undefined and will never be.

Edited August 15, 2016 by Function

[Sriman Dutta]

Instead of taking (1-1)=0, we can cancel it out from the numerator and denominator.

It is not an 'exact' maths, so just a twisting problem.

[Function]

There is no such things as "not an exact" maths.

 

It is false to cancel out (1-1)/(1-1) as that is, undeniably, the same as 0/0

[Endy0816]

Can cancel out because x/x=1.

 

You can see quickly begin to see the problems allowing division by zero introduces.

[Function]

Can cancel out because x/x=1.

 

[math]\Leftrightarrow x\neq 0[/math]

 

And in no other case. And since [math]x=1-1=0[/math], it is false.

[freekundli]

0/0 can be anything.
like:
0*2 = 0
i.e: 0/0 = 2.

Now:
0*x = 0 or 0/0 = X, where x can take any damn value.

[Function]

0/0 can be anything.

like:

0*2 = 0

i.e: 0/0 = 2.

 

Now:

0*x = 0 or 0/0 = X, where x can take any damn value.

 

I'm not convinced that that is true. But I generally don't feel the need to go into discussion with someone from India when it comes to maths.

[Commander]

Comment withdrawn

Edited August 24, 2016 by Commander

[Function]

Comment withdrawn

 

Boo.

[Joatmon]

(2*(6-(3*2)))/ (1*(8-(4*2))) should do it

 

or if you would prefer it to equal 3:-

(3*(6-(3*2)))/(1*(8-(4*2)))

 

Edited September 4, 2016 by Joatmon

[John Cuthber]

 

I'm not convinced that that is true. But I generally don't feel the need to go into discussion with someone from India when it comes to maths.

What has India got to do with it?

[Function]

What has India got to do with it?

 

Just another lame stereotype.