ku Posted April 30, 2005 Posted April 30, 2005 How do you know what limits to put when double integrating. For example for the joint probability distribution function [math]f(x,y)= \begin{cases} 2 & \mbox{if } 0 \leq y \leq x \leq 1\\ 0 & \mbox{elsewhere} \end{cases} [/math] we want to calculate the marginal probability density function of X which is [math]f(x)=\int_{-\infty}^{\infty}f(x,y)dy = \int_{0}^{x}2 dy = 2x[/math]. How come 0 and x are used as limits? Why couldn't we have picked, say, 0 and 1?
swansont Posted April 30, 2005 Posted April 30, 2005 How do you know what limits to put when double integrating. For example for the joint probability distribution function [math]f(x' date='y)= \begin{cases} 2 & \mbox{if } 0 \leq y \leq x \leq 1\\ 0 & \mbox{elsewhere} \end{cases} [/math'] we want to calculate the marginal probability density function of X which is [math]f(x)=\int_{-\infty}^{\infty}f(x,y)dy = \int_{0}^{x}2 dy = 2x[/math]. How come 0 and x are used as limits? Why couldn't we have picked, say, 0 and 1? Because the value of the function depends on whether y>x or not If the functional value had depended on a hard value for y, you would integrate to that limit.
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