Guest Skara Posted May 4, 2005 Posted May 4, 2005 Gah!! I've tried and tried. Can someone please help me real quick with these two identities? [math]sin^2(x)(1 + cot^2(x)) = 1[/math] and [math]tan(x) + cot(x) = sec(x)csc(x)[/math] I keep getting places, but nowhere helpful... Edit: LaTeX. nice. ^^;
Ducky Havok Posted May 4, 2005 Posted May 4, 2005 For the first one, just foil it out and rewrite [math]cot^{2}(x)[/math] as [math]\frac{cos^{2}(x)}{sin^{2}(x)}[/math]. You get [math]sin^{2}(x)+cos^{2}(x)=1[/math] which is a common identity. For the second, rewrite it as [math]\frac{sin(x)}{cos(x)}+\frac{cos(x)}{sin(x)}[/math]. After you cross multiply and add them together, you get [math]\frac{sin^{2}(x)+cos^{2}(x)}{cos(x)sin(x)}[/math]. The top is equal to 1 (the identity in your first problem), and when you break apart the bottom and rewrite it it is [math]sec(x)csc(x)[/math]
Guest Skara Posted May 4, 2005 Posted May 4, 2005 Thank you!! Sometimes it just takes another pair of eyes! You've been a big help. --Skara
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